Example 6.5. The lowest level of an impounding reservoir, situated in hills and being used as a source of supply, is higher than the lepel of the service reservoir by 150 metres and the distance between them is 50 km. The storgge Teormoir and the service reservoir were originally connected by a single pipe line designed to carry a max. daily. demand' of 24 million litres per day. However, it was later found necessary to increase the supply to 35 million litres ner day. It was, therefore, decided to lay another pipe of the same diameter alongside the first one in a certain reqd. length and cross-connected. Calculate the dia. of the pipes and the length of second pipe required to be laid. Make use of William Hazen's equation. Also derive an expression expressing H, in terms of L and d from the original William Hazen's formula. Assume C7 = 120. %3D
Example 6.5. The lowest level of an impounding reservoir, situated in hills and being used as a source of supply, is higher than the lepel of the service reservoir by 150 metres and the distance between them is 50 km. The storgge Teormoir and the service reservoir were originally connected by a single pipe line designed to carry a max. daily. demand' of 24 million litres per day. However, it was later found necessary to increase the supply to 35 million litres ner day. It was, therefore, decided to lay another pipe of the same diameter alongside the first one in a certain reqd. length and cross-connected. Calculate the dia. of the pipes and the length of second pipe required to be laid. Make use of William Hazen's equation. Also derive an expression expressing H, in terms of L and d from the original William Hazen's formula. Assume C7 = 120. %3D
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![Example 6.5. The lowest level of an impounding reservoir, situated in hills
and being used as a source of supply, is higher than the lepel of the service
woservoir by 150 metres and the distance between them is 50 km. The storgge
eruoir and the service reservoir were originally connected by a single pipe
line designed to carry a max. daily. demand' of 24 million litres per day
However, it was later found necessary to increase the supply to 35 million litres
per day. It was, therefore, decided to lay another pipe of the same diameter
alongside the first one in a certain reqd. length and cross-connected. Calculate
the dia. of the pipes and the length of second pipe required to be laid. Make use
of William Hazen's equation. Also derive an expression expressing H, in terms
of L and d from the original William Hazen's formula. Assume CH = 120.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fae1ac367-f302-4ef9-abb5-a867db7d3560%2Fc3ef980f-0f0d-44d6-9ded-715d3794a0fb%2Fdoaio9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Example 6.5. The lowest level of an impounding reservoir, situated in hills
and being used as a source of supply, is higher than the lepel of the service
woservoir by 150 metres and the distance between them is 50 km. The storgge
eruoir and the service reservoir were originally connected by a single pipe
line designed to carry a max. daily. demand' of 24 million litres per day
However, it was later found necessary to increase the supply to 35 million litres
per day. It was, therefore, decided to lay another pipe of the same diameter
alongside the first one in a certain reqd. length and cross-connected. Calculate
the dia. of the pipes and the length of second pipe required to be laid. Make use
of William Hazen's equation. Also derive an expression expressing H, in terms
of L and d from the original William Hazen's formula. Assume CH = 120.
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