Example 3-22. If 6n tickets numbered 0, 1, 2, ..., 6n – 1 are placed in a bag and three are drawn out, show that the chance that the sum of the numbers on them is equal to 6n is 3n(6n - 1) (6n – 2).

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 31E
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Example 3-22. If 6n tickets numbered 0, 1, 2, ..., 6n – 1 are placed in a bag and three
are drawn out, show that the chance that the sum of the numbers on them is equal to 6n is
3n(6n – 1) (6n – 2).
Transcribed Image Text:Example 3-22. If 6n tickets numbered 0, 1, 2, ..., 6n – 1 are placed in a bag and three are drawn out, show that the chance that the sum of the numbers on them is equal to 6n is 3n(6n – 1) (6n – 2).
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