Example 2B.2: A 15-cm by 15-cm circuit board is being cooled by air. It is dissipating 890 W/m² of heat to the air from its top surface. The air approaches the circuit board at 25 °C with a velocity of 6 m/s. Determine the surface temperature of the circuit board at the end of the board. Assume the flow to be turbulent at the leading edge of the board since the electronic components are expected to act as turbulators. For air properties evaluations assume a film temperature of 35 °C. Given: Circuit board geometry – length, L = 0.15 m, width, W = 0.15 m Convective heat flux to air, q'" = 890 W/m² Free-stream temp., T = 25 °C. Free-stream velocity, U» = 6 m/s %3D Assumption: Steady state. Only mode of heat transfer from the board is convection. Film temperature is T; = 35°C. Properties are considered constant and uniform. Flow is turbulent. Air is an ideal gas. Properties: Air properties at 35°C: k = 0.0265 W/m°C; v = 16.5×10-6 m²/s; Pr = 0.7 %3D

Example 2B.2: A 15-cm by 15-cm circuit board is being cooled by air. It is dissipating 890 W/m² of heat to the air from its top surface. The air approaches the circuit board at 25 °C with a velocity of 6 m/s. Determine the surface temperature of the circuit board at the end of the board. Assume the flow to be turbulent at the leading edge of the board since the electronic components are expected to act as turbulators. For air properties evaluations assume a film temperature of 35 °C. Given: Circuit board geometry – length, L = 0.15 m, width, W = 0.15 m Convective heat flux to air, q'" = 890 W/m² Free-stream temp., T = 25 °C. Free-stream velocity, U» = 6 m/s %3D Assumption: Steady state. Only mode of heat transfer from the board is convection. Film temperature is T; = 35°C. Properties are considered constant and uniform. Flow is turbulent. Air is an ideal gas. Properties: Air properties at 35°C: k = 0.0265 W/m°C; v = 16.5×10-6 m²/s; Pr = 0.7 %3D

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Properties of Fluids

The term fluid represents a type of substance that can easily change its shape under any external pressure/force and can flow. Fluids can acquire any shape in which it is stored and can resist normal stresses but cannot resist shear stress in rest condition. Whenever external shear stress is applied to fluids, it starts to flow. The fluids may be liquid or gas. Example- water, air, etc.

Question

Corection the following number k=.02625,Kinematic viscosity(fancy v)=16.55*10^-6m^2/s,Pr=.7

Re(x=L)=54380

Nu(x)=170.1

h(x=L)=29.8

Ts(l)=54.9C

Find out the total convective heat transfer rate from
the board in Example 2B.2 (solve the bolded part)
Example 2B.2: A 15-cm by 15-cm circuit board is being cooled by air. It is dissipating 890 W/m² of
heat to the air from its top surface. The air approaches the circuit board at 25 °C with a velocity of
6 m/s. Determine the surface temperature of the circuit board at the end of the board. Assume the
flow to be turbulent at the leading edge of the board since the electronic components are expected to
act as turbulators. For air properties evaluations assume a film temperature of 35 °C.
Given: Circuit board geometry – length, L = 0.15 m, width, W = 0.15 m
Convective heat flux to air, q' = 890 W/m²
Free-stream temp., T = 25 °C. Free-stream velocity, U» = 6 m/s
Assumption: Steady state. Only mode of heat transfer from the board is convection. Film temperature
is T¡ = 35°C. Properties are considered constant and uniform. Flow is turbulent. Air is an ideal gas.
Properties: Air properties at 35°C: k = 0.0265 W/m°C; v = 16.5×10-6 m²/s; Pr = 0.7

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