Example 2:- Refrigerant-134a enters the compressor of a refrigerator as superheated vapor at 0.14 MPa and -10°C at a rate of 0.05 kg/s and leaves at 0.8 MPa and 50°C. The refrigerant is cooled in the condenser to 26°C and 0.72 MPa and is throttled to 0.15 MPa. Disregarding any heat trans fer and pressure drops in the connecting lines between the components; determine (a) the rate of heat removal from the refrigerated space and the power input to the compressor, and (b) the coefficient of performance of the refrigerator.

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SUBJECT: THERMODYNAMIC
COURSE: II
ASSI.LACTURE: NATIQ ABBAS
Еxample 2:-
Refrigerant-134a enters the compressor of a refrigerator as superheated
vapor at 0.14 MPa and -10°C at a rate of 0.05 kg/s and leaves at 0.8 MPa
and 50°C. The refrigerant is cooled in the condenser to 26°C and 0.72 MPa
and is throttled to 0.15 MPa. Disregarding any heat trans fer and pressure
drops in the connecting lines between the components; determine (a) the rate
of heat removal from the refrigerated space and the power input to the
compressor, and (b) the coefficient of performance of the refrigerator.
Solution: -
da
P 0.14 MPa
T=-10 C
246.36 kJ/kg
OF
SAMARRA
P 0.8 MPa
h2 = 286.69 kJ/kg
P 0.72 MPa
T - 26 C
- hg = 87.83 kJ/kg
ha =h, = 87.83 KJ/kg
h4 = h3 (throttling) h4 87.83 kJ/kg
0.8 MPa
50°C
0.72 MPa
26 C
0.15 MPa
0.14 MPa
-10°C
SUBIECT: THERMODYNAMIC
COURSE: II
ASSI.LACTURE: NATIO ABBAS
RING
Transcribed Image Text:SUBJECT: THERMODYNAMIC COURSE: II ASSI.LACTURE: NATIQ ABBAS Еxample 2:- Refrigerant-134a enters the compressor of a refrigerator as superheated vapor at 0.14 MPa and -10°C at a rate of 0.05 kg/s and leaves at 0.8 MPa and 50°C. The refrigerant is cooled in the condenser to 26°C and 0.72 MPa and is throttled to 0.15 MPa. Disregarding any heat trans fer and pressure drops in the connecting lines between the components; determine (a) the rate of heat removal from the refrigerated space and the power input to the compressor, and (b) the coefficient of performance of the refrigerator. Solution: - da P 0.14 MPa T=-10 C 246.36 kJ/kg OF SAMARRA P 0.8 MPa h2 = 286.69 kJ/kg P 0.72 MPa T - 26 C - hg = 87.83 kJ/kg ha =h, = 87.83 KJ/kg h4 = h3 (throttling) h4 87.83 kJ/kg 0.8 MPa 50°C 0.72 MPa 26 C 0.15 MPa 0.14 MPa -10°C SUBIECT: THERMODYNAMIC COURSE: II ASSI.LACTURE: NATIO ABBAS RING
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