Example 18.9: A two hinged parabolic arch has a span 30 m and a rise of 7.5 m. The M.I. of arch section is proportional to sec 0, where 0 is the slope of the arch axis at any pont with the horizontal. Calculate the horizontal thrust caused in the arch due to rise of temperature 25°F. The value of E = 2 x 10 kN/m2 and hte co-efficient of expansion 10 m. 6 x 10-6 per degree F The M.I. at crown is 1.25 x
Example 18.9: A two hinged parabolic arch has a span 30 m and a rise of 7.5 m. The M.I. of arch section is proportional to sec 0, where 0 is the slope of the arch axis at any pont with the horizontal. Calculate the horizontal thrust caused in the arch due to rise of temperature 25°F. The value of E = 2 x 10 kN/m2 and hte co-efficient of expansion 10 m. 6 x 10-6 per degree F The M.I. at crown is 1.25 x
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![Example 18.9: A two hinged parabolic arch has a span 30 m and a rise of 7.5 m. The M.I. of arch
section is proportional to sec 0, where 0 is the slope of the arch axis at any pont with the horizontal.
Calculate the horizontal thrust caused in the arch due to rise of temperature 25°F. The value of E = 2
x 10$ kN/m2 and hte co-efficient of expansion
10 m.
6 x 10-6
per degree F. The M.I. at crown is 1.25 x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8f9732b5-186f-4b01-86ec-7af8b21216a3%2F9f09c455-a65b-429e-b9e2-240260a1b084%2Fd8df2t_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Example 18.9: A two hinged parabolic arch has a span 30 m and a rise of 7.5 m. The M.I. of arch
section is proportional to sec 0, where 0 is the slope of the arch axis at any pont with the horizontal.
Calculate the horizontal thrust caused in the arch due to rise of temperature 25°F. The value of E = 2
x 10$ kN/m2 and hte co-efficient of expansion
10 m.
6 x 10-6
per degree F. The M.I. at crown is 1.25 x
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