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EXAMPLE 13.5 The rate of decomposion of aomethane (C,H,N) is sudied by monitoring the parial pressure of the reactant as a function of time: CH;¬N=N=CH/(9) → N/(6) + C,H(9) | The data obtained at 300°C are shown in the following table: Partial Pressure of Time (s) Azomethane (mmHg) 284 100 220 150 193 200 170 250 150

EXAMPLE 13.5 The rate of decomposion of aomethane (C,H,N) is sudied by monitoring the parial pressure of the reactant as a function of time: CH;¬N=N=CH/(9) → N/(6) + C,H(9) | The data obtained at 300°C are shown in the following table: Partial Pressure of Time (s) Azomethane (mmHg) 284 100 220 150 193 200 170 250 150

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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provide the given, required, and do the cancellations
EXAMPLE 13.5 The rae of dompostion of zomehane (C;H,N, is sudid by monioring the parial pressure of the reactant as a function of time: CH;–N=N-CH(g) – → N49) + C}H(8) The data obtained at 300°C are shown in the following table: Partial Pressure of Time (s) Azomethane (mmHg) 284 100 220 150 193 200 170 250 150 300 132
Transcribed Image Text:EXAMPLE 13.5 The rae of dompostion of zomehane (C;H,N, is sudid by monioring the parial pressure of the reactant as a function of time: CH;–N=N-CH(g) – → N49) + C}H(8) The data obtained at 300°C are shown in the following table: Partial Pressure of Time (s) Azomethane (mmHg) 284 100 220 150 193 200 170 250 150 300 132
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