Ex. 29 : A steel wire of length 2.5 m has an area of cross-section 8 x 10-3 cm?. A load of 10 kg is suspended from one end and the other end is fixed. Calculate the elongation. (Y for steel = 2 x 1011 N/m2). %3D
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- what is the percentage elongation of an elastic with a cross section of 5 cm2 If the force of 15 N is applied to the end of it, young's module is 4 x 10^5 PaA 210-kg load is hung on a wire of length of 3.30 m, cross-sectional area 2.00 x 10- m2, and Young's modulus 8.00 x 1010 N/m2. What is its increase in length? mmA 1.05-m-long rod of negligible weight is supported at its ends by wires A and B of equal length (the figure (Figure 1)). The cross-sectional area of A is 2.14 mm? and that of B is 3.77 mm2. Young's modulus for wire A is 2.00x101 Pa; that for B is 1.10x1011 Pa. Figure < 1 of 1 B 1.05 m
- Young's modulus for compression of human bone is approximately 9x10⁹ N/m^2. Assume that a femur has length L. Under compression it can withstand a stress (= force/area) equal to 8. By what length would the femur compress for this stress? L = 52.80 cm; S = 7.500x107 N/m^2; (in m) OA: 9.227x10-4 OB: 1.153x10-3 OC: 1.442x10-3 D: 1.802x10-3 OE: 2.253x10-3 OF: 2.816x10-3 OG: 3.520x10-3 OH: 4.400x10-3Item 18 You apply a force of magnitude F1 to one end of a wire and another force F in the opposite direction to the other end of the wire. The cross-sectional area of the wire is 8.00 mm?. You measure the fractional change in the length of the wire, Al/lo, for several values of F. When you plot your data with Al/lo on the vertical axis and F (in units of N) on the horizontal axis, the Part A What is the value of Young's modulus for this wire? data lie close to a line that has slope 8.0 x 10-7N-1. Express your answer with the appropriate units. Y = Value Units Submit Request Answer Provide Feedback22 A cable used to elevate heavy materials like steel beams must be tough enough to withstand breaking even under a load of 1.0 x 10^6 N. For safety, the cable must support twice that load. What cross-sectional area should the cable have if it's to be made of steel? (Report answer in 2 SF; unit: m^2) *
- Comic-book superheroes are sometimes able to punch holes through steel walls. (a) If the ultimate shear strength of steel is taken to be 2.50 x 109 Pa, what force is required to punch through a steel plate 2.30 cm thick? Assume the superhero's fist has cross-sectional area of 9.00 x 101 cm2 and is approximately circular. (b) Qualitatively, what would happen to the superhero on delivery of the punch? What physical law applies?A high-speed lifting mechanism supports a 840-kg object with a steel cable that is 31.0 m long and 4.00 cm2 in cross-sectional area. (a) Determine the elongation of the cable. mm(b) By what additional amount does the cable increase in length if the object is accelerated upwards at a rate of 2.7 m/s2? mm(c) What is the greatest mass that can be accelerated upward at 2.7 m/s2 if the stress in the cable is not to exceed the elastic limit of the cable, which is 2.2 ✕ 108 Pa? kgA cable used to lift heavy materials can resist breaking even under a load of 1 meganewtons. The steel cable must support twice that load for safety purposes. By how much the steel cable will stretch if it carries 1 meganewtons of load? Assume 8.0 m initial length of the cable. Group of answer choices 0.01 m 0.001 m 0.2 m 0.1 m 0.02 m 0.002 m
- 2. Let's look at the femur – the largest, longest, and strongest bone of the human skeleton. Let's do some calculation to see if it makes sense. How much does the femur shorten when you stand on one foot? (With no stress the femur is about 0.5 m long. The cross-sections effective area is approximately 370 mm2.) would happen if you try to lift a truck? The femur is probably going to break. Femur is considered a stiff 3. ultimate strength X fracture yield but fragile material; the bone will break under a large E enough force. The linear relationship (Hooke's law) only applies for an elastic region. Beyond this the material post-yield strain will begin to yield and eventually fracture. Strain 4. Assume the bone will fracture if more than 1.5 x 108 N/m2 is exerted. What is the maximum force that can be exerted on the femur bone? StressA fishing rope of length (74+ 50) m has the diameter (74 + 5) mm. When a weight of (74 +200) N is hung on the rope, the extension is (74 + 50) mm. Calculate,i. cross-sectional area of the fishing ropeii. strainThe total cross-sectional area of the load-bearing calcified portion of the two forearm bones (radius and ulna) is approximately 2.0 cm2. During a car crash, the forearm is slammed against the dashboard. The arm comes to rest from an initial speed of 80 km/h in 4.5 ms. If the aum has an effective mass of 3.0 kg, what is the compressional stress that the arm withstands during the crash? Pa Need Help? Read It