### Item 12A 1.05-m-long rod of negligible weight is supported at its ends by wires \(A\) and \(B\) of equal length (the figure [Figure 1]). The cross-sectional area of \(A\) is 2.37 \( \text{mm}^2 \) and that of \(B\) is 4.44 \( \text{mm}^2 \). Young's modulus for wire \(A\) is \(2.40 \times 10^{11} \, \text{Pa}\); that for \(B\) is \(1.10 \times 10^{11} \, \text{Pa}\).**Part A**At what point along the rod should a weight \(w\) be suspended to produce equal stresses in \(A\) and \(B\)?Express your answer in meters.\[ d = \quad \text{m from wire } A \]*Submit**Incorrect; Try Again; 4 attempts remaining***Part B**At what point along the rod should a weight \(w\) be suspended to produce equal strains in \(A\) and \(B\)?Express your answer in meters.\[ d = \quad \text{m from wire } A \]*Submit***Figure**![Figure](https://exampleDomain/fakeImageUrl.jpg): A schematic diagram showing a horizontal rod, 1.05 meters in length, supported by two vertical wires, labeled \(A\) and \(B\), at each end of the rod. A weight \(w\) is suspended from a point along the rod.**Diagram Explanation:**The diagram illustrates a 1.05-meter-long horizontal rod with vertical wires \(A\) and \(B\) attached at its ends. The weight \(w\) is shown hanging from a point along the rod, indicating the need to determine the position \(d\) where the weight should be placed to achieve specific stress or strain conditions in the wires. This setup is used to explore concepts related to mechanical stress and strain in the context of engineering and physics.

A 1.05-m-long rod of negligible weight is supported at its ends by wires A and B of equal length (the figure (Figure 1)). The cross-sectional area of A is 2.37 mm² and that of Bis 4.44 mm². Young's modulus for wire A is 2.40×1011 Pa; that for B is 1.10×10¹1 Pa. Figure W 1.05 m B <1 of 1 Part A At what point along the rod should a weight w be suspended to produce equal stresses in A and B? Express your answer in meters. VE ΑΣΦ ? d= m from wire A Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B At what point along the rod should a weight w be suspended to produce equal strains in A and B? Express your answer in meters. ΠΫΠΙ ΑΣΦ ? m from wire A d= Submit < Return to Assignment Request Answer Provide Feedback

A 1.05-m-long rod of negligible weight is supported at its ends by wires A and B of equal length (the figure (Figure 1)). The cross-sectional area of A is 2.37 mm² and that of Bis 4.44 mm². Young's modulus for wire A is 2.40×1011 Pa; that for B is 1.10×10¹1 Pa. Figure W 1.05 m B <1 of 1 Part A At what point along the rod should a weight w be suspended to produce equal stresses in A and B? Express your answer in meters. VE ΑΣΦ ? d= m from wire A Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B At what point along the rod should a weight w be suspended to produce equal strains in A and B? Express your answer in meters. ΠΫΠΙ ΑΣΦ ? m from wire A d= Submit < Return to Assignment Request Answer Provide Feedback

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: A (2 m)-long steel wire in a musical instrument has a radius of (0.3 mm). When the wire is under a…

Q: A bar ACB has is subjected to an external load at C, and it is supported either end by a cable as…

A: We need to calculate the smallest area of cross section possible for the two cables at the end of…

Q: Find the minimum diameter of an | = 15.1 m long tungsten wire that will stretch no more than 7.00 mm…

Q: Asolid copper cube has an edge length of 85.0 cm. How much stress must be applied to the cube to…

A: Here in this Question The Edge length of the copper cube is given to be 85.0 cm and it has been…

Q: A brass wire with Young’s modulus of 92.0 GPa is 1.95 m long and has a cross-sectional area of 5.00…

A: The objective of the question is to find out how much a brass wire stretches when a certain weight…

Q: Humans can bite with a force of approximately 796 N. If a human tooth has the Young's modulus of…

Q: TTM i. Figure 4 shows a 12 kg weight suspended by a 0.3 m vertical copper wire with cross sectional…

A: Concept: In order to calculate the Strain in each of the wire we will firstly calculate the stress…

Q: A copper wire of length 7.9 m, cross sectional area 2 x 10 m²and Young's modulus 11 x 1010 N/m has a…

Q: An aluminum specimen 15 in long and in in diameter is subjected to tensile stress. The new length of…

Q: A leg has 1.4 m shaft of bone with an average cross sectional area of 3x10-4 m². What is the amount…

Q: A 210-kg load is hung on a wire of length of 3.30 m, cross-sectional area 2.00 x 10-5 m2, and…

A: mass of load (m) =210 kg initial length of Wire (L0) = 3.3 m Cross sectional area of Wire (A) = 2.0…

Q: A 1.05-m-long rod of negligible weight is supported at its ends by wires A and B of equal length…

A: This question involves two concepts: (A) Free body diagram and subsequent condition for the static…

Q: The beam is supported by a pin at A and a short link BC. Figure 0.5m 1 m 4P 1.5 m 4P 1.5 m 0.5m 1 of…

Q: A wire of length 1.5 m and of radius 0.4 mm is stretched by 1.2 mm on loading. If the Young’s…

A: Given Data :Length L = 1.5 mRadius R = 0.4 mm = 0.4×10-3 m = 4×10-4 mExtension ∆x = 1.2 mm =…

Q: A copper wire of length 23.179 is designed to withstand a maximum tension of 657 N and 0.627%…

A: Given Length of copper wire L = 23.179 m Tension T = 657 N Strain ∆L/L × 100 = 0.627 % ∆L/L =…

Q: An object with a mass equal to 300 kg is hung on a wire of length 5.00 m and cross-sectional area of…

Q: A steel wire of length 1.97 m with circular cross section must stretch no more than 0.240 cm when a…

Q: A spider silk line has a circular cross section. Its diameter is 7.14 micrometers. Its unstretched…

A: When spider changes from the thread, stress will be developed in it , whichbleads yo the expansion…

Q: Humans can bite with a force of approximately 807 N. If a human tooth has the Young's modulus of…

A: The equation for Young's modulus is given by, Y=σe (1) Here, σ is the stress and e is the strain.…

Q: steel wire of length 1.93 m with a circular cross-section must stretch no more than 0.240 cm when a…

A: Dear student The Young modulus is defined as: Y = Stress/ Strain Here stress = Force / Area Strain =…

Q: Humans can bite with a force of approximately 808 N. If a human tooth has the Young's modulus of…

A: Using the equation for Young's Modulus, Y=FLA∆L∆L=FLAY

Q: A steel wire of length 1.93 m with a circular cross-section must stretch no more than 0.240 cm when…

Q: determine the change in the tooth's length

A: Given data: The force applied during bite is: F = 796 N The cross-sectional area of tooth is: A…

Q: What is the maximum length of steel cable that can hang vertically supported from one end of the…

A: A cable hangs vertically supported from one end of the steel cable. And the density of this steel is…

Q: A 15.0-kg mass fastened to the end of a steel wire with an unstretched length of 0.650 m is whirled…

Q: A 180-kg load is hung on a wire of length of 4.50 m, cross-sectional area 2.000 x 10-5 m2, and…

A: Given data: Mass (m) = 180 kg Length (L) = 4.50 m Cross sectional area (A) = 2.000×10-5 m2 Young…

Concept explainers

Mechanical Properties of Solids

There are three types of matter- solid, liquid and gas. Out of them, solids have a rigid shaped and size. The intermolecular forces of attractions in solids are greatest. Mechanical properties are the physical properties of a material which it shows, when it is provided with certain amount of force or load. These properties are to be kept in mind for various purposes. When a force is applied to an object, the object may or may not get deformed depending upon its elastic property. But every time the object develops a restoring force against the force applied. This is commonly known as stress. If the object changes its dimensions due to the force applied it develops strain ( which is the ratio of change in dimension to the original dimension).

Question

### Item 12

A 1.05-m-long rod of negligible weight is supported at its ends by wires \(A\) and \(B\) of equal length (the figure [Figure 1]). The cross-sectional area of \(A\) is 2.37 \( \text{mm}^2 \) and that of \(B\) is 4.44 \( \text{mm}^2 \). Young's modulus for wire \(A\) is \(2.40 \times 10^{11} \, \text{Pa}\); that for \(B\) is \(1.10 \times 10^{11} \, \text{Pa}\).

**Part A**

At what point along the rod should a weight \(w\) be suspended to produce equal stresses in \(A\) and \(B\)?
Express your answer in meters.

\[ d = \quad \text{m from wire } A \]

*Submit*
*Incorrect; Try Again; 4 attempts remaining*

**Part B**

At what point along the rod should a weight \(w\) be suspended to produce equal strains in \(A\) and \(B\)?
Express your answer in meters.

\[ d = \quad \text{m from wire } A \]

*Submit*

**Figure**
![Figure](https://exampleDomain/fakeImageUrl.jpg): A schematic diagram showing a horizontal rod, 1.05 meters in length, supported by two vertical wires, labeled \(A\) and \(B\), at each end of the rod. A weight \(w\) is suspended from a point along the rod.

**Diagram Explanation:**
The diagram illustrates a 1.05-meter-long horizontal rod with vertical wires \(A\) and \(B\) attached at its ends. The weight \(w\) is shown hanging from a point along the rod, indicating the need to determine the position \(d\) where the weight should be placed to achieve specific stress or strain conditions in the wires. This setup is used to explore concepts related to mechanical stress and strain in the context of engineering and physics.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

A scanning electron micrograph of xylem vessels in a corn root shows the vessels magnified by a factor of 598. In the micrograph the xylem vessel is 2.80 cm in diameter. a. What is the diameter of the vessel itself? b. By what factor has the cross-sectional area of the vessel been increased in the micrograph?
1. The setup shown by the diagram below was used to calculate the force experienced by a small mass m situated at a distance r from the geometric center of a spherical shell with mass M, radius R, and a wall thickness of t. M C dᎾ R 0 Rde A Rsine B r Ф dF Ф m If the mass is situated outside the spherical shell, the force can be calculated by integration from l = (r - R) to l= (r+ R), as shown here: l=r+R R - [ &F="TOmp: +(1+²²=² ) We SdF=fGmpat- de l=r-R What would the limits of integration be if the mass were situated inside the spherical shell? Include a labeled diagram to represent this situation.
You apply a force of magnitude F_ to one end of a wire and another force F_ in the opposite direction to the other end of the wire. The cross-sectional area of the wire is 8.00 mm2. You measure the fractional change in the length of the wire, Al/lo, for several values of F. When you plot your data with Al/lo on the vertical axis and F (in units of N) on the horizontal axis, the data lie close to a line that has slope 8.0 x 10-7 N-1. Part A What is the value of Young's modulus for this wire? Express your answer with the appropriate units. Y = Value Units Submit Request Answer Provide Feedback
1. The setup shown by the diagram below was used to calculate the force experienced by a small mass m situated at a distance r from the geometric center of a spherical shell with mass M, radius R, and a wall thickness of t. M = с dᎾ R 0 Rde A B Rsine r l r Ф p dF l If the mass is situated outside the spherical shell, the force can be calculated by integration from l = (r - R) (r+ R), as shown here: to l l=r+R R - 5 d² - T Gompert (1+²^²=R²) 21 SdF = Jae l=r-R m What would the limits of integration be if the mass were situated inside the spherical shell? Include a labeled diagram to represent this situation.
The homogeneous wire ABCD is bent as shown and is attached to a hinge at C. Determine the length L that results in portion BCD of the wire being horizontal. +200 mm -L B !C 150 mm
The tolerance is positve negative 1 in the 2nd significant digit
The bracket, which is fastened to a wall by anchor bolts at A and B is loaded by the force P = 120 N and the couple C = 140 N.m. Replace P and C with (a) an equivalent force-couple system, the force of which acts at A; and (b) two vertical forces, one acting at A and the other at B.
QUESTION 1 The linear mass density (A) of a rod of length L is given by A = a+ Bx2 where a and B are constants and x is the distance from one end. What is the total mass of this rod? a + BL2 aL + (BL³)/ 3 (a+ Bx2)L O al + (BL2)/ 2
2
Q1: The fibers in a unidirectional lamina have a diameter of 12 μm and weight fraction of 60%. The density of fibers is 1.5 of the density of the epoxy. Find the center-to-center spacing of the fibers if: 1. Packed in a square array in the epoxy matrix. 2. Packed in a triangular array in the epoxy matrix.
04: The fibers in a unidirectional lamina have a diameter of 12 um and weight fraction of 60%. The density of fibers is 1.5 of the density of the epoxy. Find the center-to-center spacing of the fibers if: i. ii. Packed in a square array in the epoxy matrix. Packed in a triangular array in the epoxy matrix.
Help.explain.