Jumping up before the elevator hits. After the cable snaps and the safety system fails, an elevator cab free-falls from a height of 34 m. During the collision at the bottom of the elevator shaft, a90 kg passenger is stopped in 6.0 ms. (Assume that neither the passenger nor the cab rebounds.)(a) What is the magnitude of the impulse on the passenger during the collision?N's(b) What is the magnitude of the average force on the passenger during the collision?NSuppose the passenger were to jump upward with a speed of 6.5 m/s relative to the cab floor just before the cab hits the bottom of the shaft. Assume the same stopping time as above.(c) What is the magnitude of the impulse on the passenger during the collision?N•s(d) What is the magnitude of the average force on the passenger during the collision?N

Change in momentum= Impluse 12 m v2= mgh v= 2ghv= 25.04 m/s a) Impluse 90 × 25.04 = 2753.6 Ns b)…

evator hits. After the cable snaps and the safety ed in 6.0 ms. (Assume that neither the passenge nagnitude of the impulse on the passenger during nagnitude of the average force on the passenger vere to jump upward with a speed of 6.5 m/s rela nagnitude of the impulse on the passenger during nagnitude of the average force on the passenger

evator hits. After the cable snaps and the safety ed in 6.0 ms. (Assume that neither the passenge nagnitude of the impulse on the passenger during nagnitude of the average force on the passenger vere to jump upward with a speed of 6.5 m/s rela nagnitude of the impulse on the passenger during nagnitude of the average force on the passenger

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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