Estimate the moles of Cu(NH3)4* formed, assuming all the original Cu2+ in the porous cup reacted to form the Cu(NH3);2+. Because [Cu?*]cup should be very small this is a reasonable approximation. Calculate the [Cu(NH3)2*] in the porous cup.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Solve both parts otherwise I will downvote
voltage before adding NH3: 0V
voltage after adding NH3: 0.34V
[Cuļcup concentration = 0.002 mol/L
[Cu]jar concentration = 0.2 mol/L
T = 298.15 K
answer question b. Calculate the [Cu(NH3)4]
in the cup
The reaction between Cut and NH3 is:
Cu2"(ag) + 4NH3(ag) 2 Cu(NH3)«(ag)
For which an equilibrium constant can be written:
[Cu(NH,),"]
K,
[Cu][NH, J'
From the observed voltage in part II (after adding NH:) and the Nemst Equation:
E = E°.
RT [Cul,
In
%3D
nF[Cu**],
b.
Estimate the moles of Cu(NH3)42+ formed, assuming all the original Cu2+ in the
porous cup reacted to form the Cu(NH3)42+. Because [Cu*cup should be very
small this is a reasonable approximation. Calculate the [Cu(NH3)2*] in the
porous cup.
Transcribed Image Text:voltage before adding NH3: 0V voltage after adding NH3: 0.34V [Cuļcup concentration = 0.002 mol/L [Cu]jar concentration = 0.2 mol/L T = 298.15 K answer question b. Calculate the [Cu(NH3)4] in the cup The reaction between Cut and NH3 is: Cu2"(ag) + 4NH3(ag) 2 Cu(NH3)«(ag) For which an equilibrium constant can be written: [Cu(NH,),"] K, [Cu][NH, J' From the observed voltage in part II (after adding NH:) and the Nemst Equation: E = E°. RT [Cul, In %3D nF[Cu**], b. Estimate the moles of Cu(NH3)42+ formed, assuming all the original Cu2+ in the porous cup reacted to form the Cu(NH3)42+. Because [Cu*cup should be very small this is a reasonable approximation. Calculate the [Cu(NH3)2*] in the porous cup.
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