Estimate how much the drug will lower a typical patient's systolic blood pressure (using a 90% confidence level). Assume the data is from a normally distributed population. Enter your answer as a tri-linear inequality accurate to three decimal places.
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Sample size n=24
Sample mean=65.7
Standard deviation=21.8
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- What is an experiment?Mercury in Tuna - Mercury, if ingested can cause severe health problems. The amount of mercury in Tuna's body tissue is much higher than other fish. It is known that the amount of mercury in Albacore tuna is normally distributed with mean 10.13 micrograms and standard deviation of 2.03 micrograms per ounce. A food company has a production line for canned albacore tuna. They regularly take random samples of 10 cans of tuna and test the amount of mercury. If the sample mean amount of mercury in tuna exceeds 12 micrograms per ounce, the production line will be stopped to find the source of contamination. Let u denote the actual population mean amount of mercury in tuna per ounce. The hypotheses for this testing situation are: Но : и —D 10.13 vs Ha : и > 10.13. What is the chance of making a Type I error using the decision rule given above? Give your answer to 4 decimal places. Your Answer: AnswerMercury in Tuna - Mercury, if ingested can cause severe health problems. The amount of mercury in Tuna's body tissue is much higher than other fish. It is known that the amount of mercury in Albacore tuna is normally distributed with mean 10.13 micrograms and standard deviation of 2.03 micrograms per ounce. A food company has a production line for canned albacore tuna. They regularly take random samples of 10 cans of tuna and test the amount of mercury. If the sample mean amount of mercury in tuna exceeds 12 micrograms per ounce, the production line will be stopped to find the source of contamination. Let u denote the actual population mean amount of mercury in tuna per ounce. The hypotheses for this testing situation are: Но : и 3D 10.13 vs Hа : н> 10.13. To calculate the chance of making a Type I error using the decision rule above, what would you use as the standard deviation for the normal distribution in your graphing calculator? Give your answer to 4 decimal places. Your Answer:…
- Mercury in Tuna - Mercury, if ingested can cause severe health problems. The amount of mercury in Tuna's body tissue is much higher than other fish. It is known that the amount of mercury in Albacore tuna is normally distributed with mean 10.13 micrograms and standard deviation of 2.03 micrograms per ounce. A food company has a production line for canned albacore tuna. They regularly take random samples of 10 cans of tuna and test the amount of mercury. If the sample mean amount of mercury in tuna exceeds 12 micrograms per ounce, the production line will be stopped to find the source of contamination. Let u denote the actual population mean amount of mercury in tuna per ounce. The hypotheses for this testing situation are: Но : и 3D 10.13 vs HA: H > 10.13. What is the chance of making a Type I error using the decision rule given above? Give your answer to 4 decimal places. Your Answer: AnswerMercury in Tuna - Mercury, if ingested can cause severe health problems. The amount of mercury in Tuna's body tissue is much higher than other fish. It is known that the amount of mercury in Albacore tuna is normally distributed with mean 10.13 micrograms and standard deviation of 2.03 micrograms per ounce. A food company has a production line for canned albacore tuna. They regularly take random samples of 10 cans of tuna and test the amount of mercury. If the sample mean amount of mercury in tuna exceeds 12 micrograms per ounce, the production line will be stopped to find the source of contamination. Let u denote the actual population mean amount of mercury in tuna per ounce. The hypotheses for this testing situation are: Но : и 3D 10.13 vs Hд : и > 10.13. What is the chance of making a Type I error using the decision rule given above? Give your answer to 4 decimal places. Your Answer:Mercury in Tuna - Mercury, if ingested can cause severe health problems. The amount of mercury in Tuna's body tissue is much higher than other fish. It is known that the amount of mercury in Albacore tuna is normally distributed with mean 10.13 micrograms and standard deviation of 2.03 micrograms per ounce. A food company has a production line for canned albacore tuna. They regularly take random samples of 10 cans of tuna and test the amount of mercury. If the sample mean amount of mercury in tuna exceeds 12 micrograms per ounce, the production line will be stopped to find the source of contamination. Let u denote the actual population mean amount of mercury in tuna per ounce. The hypotheses for this testing situation are: Но : и 3D 10.13 vs HA : и > 10.13. 10.13 vs HA: H > 10.13. To calculate the chance of making a Type I error using the decision rule above, what would you use as the mean for the normal distribution in your graphing calculator? Your Answer:
- Mercury in Tuna - Mercury, if ingested can cause severe health problems. The amount of mercury in Tuna's body tissue is much higher than other fish. It is known that the amount of mercury in Albacore tuna is normally distributed with mean 10.13 micrograms and standard deviation of 2.03 micrograms per ounce. A food company has a production line for canned albacore tuna. They regularly take random samples of 10 cans of tuna and test the amount of mercury. If the sample mean amount of mercury in tuna exceeds 12 micrograms per ounce, the production line will be stopped to find the source of contamination. Let u denote the actual population mean amount of mercury in tuna per ounce. The hypotheses for this testing situation are: Ho : µ = 10.13 vs HA : µ > 10.13. To calculate the chance of making a Type I error using the decision rule above, what would you use as the mean for the normal distribution in your graphing calculator? Your Answer:Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of womenMercury in Tuna amount of mercury in Tuna's body tissue is much higher than other fish. Mercury, if ingested can cause severe health problems. The It is known that the amount of mercury in Albacore tuna is normally distributed with mean 10.13 micrograms and standard deviation of 2.03 micrograms per ounce. A food company has a production line for canned albacore tuna. They regularly take random samples of 10 cans of tuna and test the amount of mercury. If the sample mean amount of mercury in tuna exceeds 12 micrograms per ounce, the production line will be stopped to find the source of contamination. Let u denote the actual population mean amount of mercury in tuna per ounce. The hypotheses for this testing situation are: Ho : µ = 10.13 vs HA : µ > 10.13. What is the power of the hypothesis test, using the decision rule given above, if the population mean amount of mercury is 11.5 micrograms per ounce? Give your answer to 4 decimal places. Your Answer: Answer
- Is narcissism a more common personality trait today than it was a few decades ago? It is known that the mean population score on the Narcissistic Personality Inventory (NPI) for students attending University of South Alabama around 20 years ago was μ= 15 (Twenge, 2010). Interested in the narcissism levels of students in the year 2020, a researcher administers the NPI to a random sample of 25 University of Alabama sophomores this Spring term. The mean NPI score from the researcher’s sample of sophomores is M = 16.5, with s = 3.4. 1. Write the null and alternative hypotheses in symbols. Possible symbols for your answer: H0, H1, μ, M, σ. 2. Calculate the standard error. 3. Find the critical value for the test statistic, assuming alpha = .05 (Use largest [i.e., most conservative] value if exact value not given in the chart) a) 2.064 b) 1.96 c) 1.98 d) 2.000The average American consumes 86 liters of alcohol per year. Does the average college student consume more alcohol per year? A researcher surveyed 15 randomly selected college students and found that they averaged 94.2 liters of alcohol consumed per year with a standard deviation of 24 liters. What can be concluded at the α = 0.05 level of significance? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer = < ≠ > H1:H1: ? p μ Select an answer ≠ = > < The test statistic? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should -------- the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean is not significantly more than 86 at αα = 0.05, so there is statistically…A child care center wants to determine if there is a relationship between how long a child naps in minutes (20,21,22,23,24,etc.,etc) and incidents of aggression (1,2,3,4,etc.,etc). What type of statistical test should be used? Group of answer choices Chi Square Independent t-test Dependent t-test ANOVA Correlation Analysis