esc STARTING AMOUNT ! AMB 0¹ F1 . X 3662 @ F2 1 # 80 F3 15 How many moles of aluminum are required to completely react with 107 6.00 M H₂SO according to the balanced chemical reaction: 2 Al(s) + 3 H₂SO (aq) → Al₂(SO),(aq) + 3 H₂(g) 0.428 ADD FACTOR NOV 7 × ( ) 0.0374 mL H₂SO M H₂SO Q 98.08 F4 1 % mol H₂ ļ F5 2 g H₂SO Question 1 of 4 tv 3 6.022 x 1023 mol Al . 107 9 F6 ANSWER g Al mol H₂SO mol Al₂(SO₂), S I MacBook Air & 428 ← 1000 F7 g H₂ 6.00 0.001 A DII mL of RESET g Al₂(SO), LH₂SO, FB D 0.963 B DD F9 . . 30 F10 .
esc STARTING AMOUNT ! AMB 0¹ F1 . X 3662 @ F2 1 # 80 F3 15 How many moles of aluminum are required to completely react with 107 6.00 M H₂SO according to the balanced chemical reaction: 2 Al(s) + 3 H₂SO (aq) → Al₂(SO),(aq) + 3 H₂(g) 0.428 ADD FACTOR NOV 7 × ( ) 0.0374 mL H₂SO M H₂SO Q 98.08 F4 1 % mol H₂ ļ F5 2 g H₂SO Question 1 of 4 tv 3 6.022 x 1023 mol Al . 107 9 F6 ANSWER g Al mol H₂SO mol Al₂(SO₂), S I MacBook Air & 428 ← 1000 F7 g H₂ 6.00 0.001 A DII mL of RESET g Al₂(SO), LH₂SO, FB D 0.963 B DD F9 . . 30 F10 .
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
can you help me and plug it in in the correct form i keep doing it and its saying im wrong
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STARTING AMOUNT
:0
F1
X
3.662
-0
F2
30
#
80
F3
15
How many moles of aluminum are required to completely react with 107
6.00 M H₂SO according to the balanced chemical reaction:
4
0.428
NOV
7
ADD FACTOR
$
x( )
X
2
0.0374
mL H₂SO M H₂SO
4
Q
F4
Al(s) +
98.08
%
1
mol H₂
0
F5
3 H₂SO (aq) →→ Al(SO),(aq) + 3 H₂(g)
2
g H₂SO
Question 1 of 4
atv
3
6.022 x 1023
mol Al
107
ņ
@
F6
ANSWER
g Al mol H₂SO
mol Al₂(SO₂),
MacBook Air
428
&
1000
F7
4
IM 2
g H₂
6.00
0.001
A
mL of
RESET
g Al₂(SO), LH₂SO
F8
D
0.963
4
*
((((
C
F9
C
A
30
F10
W](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F574bf9f3-609e-4870-b103-4ad8e97b08b1%2F61ec01d8-7c4d-4f3a-a4f4-6bb12d01c692%2Fwfbw26n_processed.jpeg&w=3840&q=75)
Transcribed Image Text:<
esc
STARTING AMOUNT
:0
F1
X
3.662
-0
F2
30
#
80
F3
15
How many moles of aluminum are required to completely react with 107
6.00 M H₂SO according to the balanced chemical reaction:
4
0.428
NOV
7
ADD FACTOR
$
x( )
X
2
0.0374
mL H₂SO M H₂SO
4
Q
F4
Al(s) +
98.08
%
1
mol H₂
0
F5
3 H₂SO (aq) →→ Al(SO),(aq) + 3 H₂(g)
2
g H₂SO
Question 1 of 4
atv
3
6.022 x 1023
mol Al
107
ņ
@
F6
ANSWER
g Al mol H₂SO
mol Al₂(SO₂),
MacBook Air
428
&
1000
F7
4
IM 2
g H₂
6.00
0.001
A
mL of
RESET
g Al₂(SO), LH₂SO
F8
D
0.963
4
*
((((
C
F9
C
A
30
F10
W
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