Ernest Rutherford (the first New Zealander to be awarded the Nobel Prize in Chemistry) demonstrated that nuclei were very small and dense by scattering helium-4 nuclei (He) from gold-197 nuclei (197Au). The energy of the incoming helium nucleus was 7.28 x 10-13 J, and the masses of the helium and gold nuclei were 6.68 x 10-27 kg and 3.29 x 10-25 kg, respectively (note that their mass ratio is 4 to 197). (Assume that the helium nucleus travels in the +x direction before the collision.) (a) If a helium nucleus scatters to an angle of 136° during an elastic collision with a gold nucleus, calculate the helium nucleus' final speed (in m/s) and the final velocity (magnitude in m/s and direction counterclockwise from the +x-axis) of the gold nucleus. 4He speed 197 Au velocity 0.0140 197 Au direction -17 14500000 m/s X m/s Xcounterclockwise from the +x-axis (b) What is the final kinetic energy (in J) of the helium nucleus? 7.02e-13 ✓ J

Ernest Rutherford (the first New Zealander to be awarded the Nobel Prize in Chemistry) demonstrated that nuclei were very small and dense by scattering helium-4 nuclei (He) from gold-197 nuclei (197Au). The energy of the incoming helium nucleus was 7.28 x 10-13 J, and the masses of the helium and gold nuclei were 6.68 x 10-27 kg and 3.29 x 10-25 kg, respectively (note that their mass ratio is 4 to 197). (Assume that the helium nucleus travels in the +x direction before the collision.) (a) If a helium nucleus scatters to an angle of 136° during an elastic collision with a gold nucleus, calculate the helium nucleus' final speed (in m/s) and the final velocity (magnitude in m/s and direction counterclockwise from the +x-axis) of the gold nucleus. 4He speed 197 Au velocity 0.0140 197 Au direction -17 14500000 m/s X m/s Xcounterclockwise from the +x-axis (b) What is the final kinetic energy (in J) of the helium nucleus? 7.02e-13 ✓ J

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Description: Ernest Rutherford (the first New Zealander to be awarded the Nobel Prize in Chemistry) demonstrated that nuclei were very small and dense by scattering helium-4 nuclei (ªHe) from gold-197 nuclei(197 Au). The energy of the incoming helium nucleus was

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Ernest Rutherford (the first New Zealander to be awarded the Nobel Prize in Chemistry) demonstrated that nuclei were very small and dense by scattering helium-4 nuclei (ªHe) from gold-197 nuclei
(197 Au). The energy of the incoming helium nucleus was 7.28 × 10-13 J, and the masses of the helium and gold nuclei were 6.68 × 10-27 kg and 3.29 × 10-25 kg, respectively (note that their mass
ratio is 4 to 197). (Assume that the helium nucleus travels in the +x direction before the collision.)
(a) If a helium nucleus scatters to an angle of 136° during an elastic collision with a gold nucleus, calculate the helium nucleus' final speed (in m/s) and the final velocity (magnitude in m/s and
direction counterclockwise from the +x-axis) of the gold nucleus.
4He speed
197 Au velocity
t
197
Au direction
14500000
0.0140
-17
m/s
X m/s
° counterclockwise from the +x-axis
(b) What is the final kinetic energy (in J) of the helium nucleus?
7.02e-13
J

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