Er- nu 275– 25(10) PΣΧ> 275) = P Vno 25 (3) = P(Z >1.6667) =1-P(Z <1.6667) =1-0.9522(Using standard normal table) %3D = 0.0478 Thus, the required proportion is 0.0478.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.6: Summarizing Categorical Data
Problem 31PPS
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Can you please help me simplify and elaborate the formula please? with detailed steps how we could calculate each aprt separately.

thank you 

P(Ex>275) = P| 2r-nu _ 275– 25(10)
Vno
PΣΧ> 275) = P
V25 (3)
= P(Z >1.6667)
=1-P(Z <1.6667)
=1-0.9522(Using standard normal table)
= 0.0478
Thus, the required proportion is 0.0478.
Transcribed Image Text:P(Ex>275) = P| 2r-nu _ 275– 25(10) Vno PΣΧ> 275) = P V25 (3) = P(Z >1.6667) =1-P(Z <1.6667) =1-0.9522(Using standard normal table) = 0.0478 Thus, the required proportion is 0.0478.
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