Sample Proportion (p) : 0.4300 (0.4300)(1–0.4300) Standard Error of p = s.e.(p) : 0.0495 100 z* Multiplier = 1.6449 Margin of Error = z* x s.e.(p) = 1.6449 × 0.0495 = 0.0814 Our Interval: p + z* X s.e.(ô) → 0.4300 ± 1.6449 × 0.0495 → (0.3486,0.5114)
Sample Proportion (p) : 0.4300 (0.4300)(1–0.4300) Standard Error of p = s.e.(p) : 0.0495 100 z* Multiplier = 1.6449 Margin of Error = z* x s.e.(p) = 1.6449 × 0.0495 = 0.0814 Our Interval: p + z* X s.e.(ô) → 0.4300 ± 1.6449 × 0.0495 → (0.3486,0.5114)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
state whether or not this resulting observed interval ended up capturing the true population proportion p of 0.45.
![Sample Proportion (p) : 0.4300
(0.4300)(1-0.4300)
Standard Error of p = s.e.(p)
= 0.0495
||
100
z* Multiplier =1.6449
Margin of Error = z* x s.e.(p)
= 1.6449 × 0.0495 = 0.0814
Our Interval: p ±z* × s.e.(ô) = 0.4300 + 1.6449 × 0.0495 → (0.3486, 0.5114)
True Proportion
0.3486
0.5114
0.0
0.2
0.4
0.6
0.8
1.0
p-hat](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F05746c0e-2bde-41f7-b21f-b6c2a3fd0725%2Fed8ea913-8e39-4ccd-ab14-f2a820db85eb%2Flwugujr_processed.png&w=3840&q=75)
Transcribed Image Text:Sample Proportion (p) : 0.4300
(0.4300)(1-0.4300)
Standard Error of p = s.e.(p)
= 0.0495
||
100
z* Multiplier =1.6449
Margin of Error = z* x s.e.(p)
= 1.6449 × 0.0495 = 0.0814
Our Interval: p ±z* × s.e.(ô) = 0.4300 + 1.6449 × 0.0495 → (0.3486, 0.5114)
True Proportion
0.3486
0.5114
0.0
0.2
0.4
0.6
0.8
1.0
p-hat
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