Equation for Standard Curve of the concentration of CuSO4 is A815= 0.0101[CuSO4]-0.0017, R2=0.9994. what is the concentration in molarity of the unknown CuSO4 concentration and include standard deviation for the data below. Serial dilution were preformed. absorbance from stand curve is 815 Dilution Ratio Absorbance (nm) 1:2 1.7412 1:4 0.8569 1:8 0.4167 1:16 0.1958

Equation for Standard Curve of the concentration of CuSO4 is A815= 0.0101[CuSO4]-0.0017, R2=0.9994. what is the concentration in molarity of the unknown CuSO4 concentration and include standard deviation for the data below. Serial dilution were preformed. absorbance from stand curve is 815 Dilution Ratio Absorbance (nm) 1:2 1.7412 1:4 0.8569 1:8 0.4167 1:16 0.1958

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter12: Spectrochemical Methods

Section: Chapter Questions

Problem 12P

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Equation for Standard Curve of the concentration of CuSO4 is A815= 0.0101[CuSO4]-0.0017, R2=0.9994. what is the concentration in molarity of the unknown CuSO4 concentration and include standard deviation for the data below. Serial dilution were preformed. absorbance from stand curve is 815 Dilution Ratio Absorbance (nm) 1:2 1.7412 1:4 0.8569 1:8 0.4167 1:16 0.1958
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Felodipine calcium channel blocker standard (0.251mg/ml) and felodipine sample (0.245mg/ml) solutions were prepared and injected to the HPLC. The peak area of felodipine standard is 275428 and the sample is 272982. The potency (purity) of felodipine standard is 98.9%. What is the assay percentage of felodipine? a. 102.23 b. 98.71 c. 101.07 d. 100.42
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The results in the table below were obtained from the analyses of Mg2+ content in an orange juice sample using a flame-AAS. Based on these results answer the following questions: (i) (ii) Replicate 1 2 3 4 Mg²+(ppm) 7.08 7.21 7.12 7.09 Calculate the mean, standard deviation and coefficient of variation (or %RSD) for the results obtained. If the certified value of the Mg2+ content of the apple juice sample is 7.45 ppm. What is the percentage of recovery for this analysis?
A volume of 250 ml of a 0.05 M solution of a reagent of formula weight (relative molecular mass) 40 was made up, the weighing being done by difference. The standard deviation of each weighing was 0.0001 g. 1 (a) What were the standard deviation and relative standard deviation of the weight of reagent used?
2. A method for analysis of codeine in prescription drugs yielded the following results when applied to a codeine- free blank: 0.01, -0.2, 0.3, 0.2, 0.0, -0.1 mg codeine. Calculate the detection limit (in terms of miligrams in codeine) at 99% confidence level, based upon the mean.
An analytical determination for manganese in an aqueous solution on gives thefollowing replicate measurements in ppm as 12.1, 12.3, 12.2, 12.2, 12.4, 12.3, 12.2, 12.4,12.2, and 12.5. Determine the following;a) The range of the datab) The meanc) Mediand) Standard deviatione) Variancef) Relative standard deviation RSD (ppt)
Concentration EDTA (M): 1.94e-3 Trial #1 Trial #2 Trial #3 Volume of Water Sample titrated (mL): 25.00 25.00 25.00 Volume EDTA used (mL): 36.23 39.00 37.77 Calculate the average of the volume of EDTA used. Calculate the number of moles of EDTA solution required to titrate the water sample. The total hardness is due to one or a combination of Ca2+, Mg2+, and Fe2+ in your sample. It is convenient to express this hardness as though it was entirely due to Ca2+. Making this assumption, determine the number of moles of Ca2+ present in the bottled water sample. The total hardness and the information on Table 1 is always listed in parts-per-million (ppm) of CaCO3 (or mg CaCO3/KgH2O). Since the density of water is 1.0 g/mL, one ppm would be the same as the number of mg of CaCO3 per liter of water. Determine the number of moles of CaCO3 present in the bottled water, assuming all the Ca2+ combine with CO32−. Calculate the number of grams of CaCO3 present and convert to mg.…
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. 100 ml boiled cooled and filtered water sample takes 9.6 ml of M/50 EDTA in titration. The Permanent hardness of the water sample in terms of ppm of CaCO3 equivalent is
Solve (c) and (d)