(Equation 1) 4 Fe2O3(s) + 20 NO2(g) + 22 H2O(l) + 5 O2(g) → 8 Fe(OH)3(s) + 20 HNO3(aq) AH= -1811.2 kJ/mol (Equation 2) Fe2O3(s) + 3 H2O (l) → 2 Fe(OH)3(s) AH = 35.6 kJ/mol (Equation 3) 20 HNO3(aq) → 5 O2(g) + 10 H2O (1) + 20 NO2(g) AH = ??????? The AH for equation 3 is: _________(express in kJ)
(Equation 1) 4 Fe2O3(s) + 20 NO2(g) + 22 H2O(l) + 5 O2(g) → 8 Fe(OH)3(s) + 20 HNO3(aq) AH= -1811.2 kJ/mol (Equation 2) Fe2O3(s) + 3 H2O (l) → 2 Fe(OH)3(s) AH = 35.6 kJ/mol (Equation 3) 20 HNO3(aq) → 5 O2(g) + 10 H2O (1) + 20 NO2(g) AH = ??????? The AH for equation 3 is: _________(express in kJ)
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Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.94QP
Related questions
Question
![(Equation 1) 4 Fe2O3(s) + 20 NO2(g) + 22 H2O(l) + 5 O2(g) → 8 Fe(OH)3(s) + 20
HNO3(aq) AH= -1811.2 kJ/mol
(Equation 2) Fe2O3(s) + 3 H2O (l) → 2 Fe(OH)3(s) AH = 35.6 kJ/mol
(Equation 3) 20 HNO3(aq) → 5 O2(g) + 10 H2O (1) + 20 NO2(g) AH = ???????
The AH for equation 3 is: _________(express in kJ)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1315573d-9a01-4c4a-b351-1b23bfce4d44%2F286fb98d-b540-40ed-b083-f318016ad24b%2Fgv5boh3_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(Equation 1) 4 Fe2O3(s) + 20 NO2(g) + 22 H2O(l) + 5 O2(g) → 8 Fe(OH)3(s) + 20
HNO3(aq) AH= -1811.2 kJ/mol
(Equation 2) Fe2O3(s) + 3 H2O (l) → 2 Fe(OH)3(s) AH = 35.6 kJ/mol
(Equation 3) 20 HNO3(aq) → 5 O2(g) + 10 H2O (1) + 20 NO2(g) AH = ???????
The AH for equation 3 is: _________(express in kJ)
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