Enzyme reactionsExampleThe reaction between nicotineamide mononucleotide and ATP to formnicotineamide-adenine dinucleotide and pyrophosphate is catalyzed by theenzyme nicotinamide mononucleotide adenylyl transferase. The followingtable provides typical data obtained at a pH of 4.95. The substrate, S, isnicotinamide mononucleotide and the initial rate, v, is the μmol ofnicotinamide-adenine dinucleotide formed in a 3-min reaction period.[S] (mM) 0.138 0.220 0.2910.560 0.766 1.460v (umol)0.148 0.1710.2340.324 0.390 0.493Determine values for Vax and Km.

Answered: Enzyme reactions Example The reaction…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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What approximation is used to determine the rate law of linear chain reactions? Justify your answer.
Give detailed Solution
The enzyme examase catalyses the following reaction, A - B where A is the reactant and B is the product A595 measurements were used to determine the catalytic activity of examase by measuring the rate at which B is produced. From this, the activity of the enzyme was determined to be 42 µmol/mL per minute. A standard albumin solution (concentration = 10 mg/mL) was used to prepare a standard curve of Abs595 vs amount of protein in mg. The protein assay was also performed using 100 uL of a 1 in 10 dilution of the original examase sample. For the absorbance measurements, it was determined that the sample used in the A595 measurement contains 1.2 mg of examase. Which of the following statements correctly gives the specific activity of examase? 1.0.35 U/mg O 2.0.035 U/mg 3. 5040 U/mg O 4.35 U/mg O 5.3.5 U/mg
2C4H6(g) → C8H12(g) At high temperatures, the compound C4H6 (1,3-butadiene) reacts according to the equation above. The rate of the reaction was studied at 625 K in a rigid reaction vessel. Two different trials, each shown with a different starting concentration, were carried out. The data were plotted in three different ways, as shown below. (a) For trial 1, calculate the initial pressure, in atm, in the vessel at 625 K. Assume that initially all the gas present in the vessel is C4H6. (Hint-this is a gas law problem from chemistry last year) (b) Use the data plotted in the graphs to determine the order of the reaction with respect to C4H6. (c) The initial rate of the reaction in trial 1 is 0.0010 mol/(L *s). Calculate the rate constant, k, for the reaction at 625 K.
Give a reaction rate for the provided mechanism and do not include the intermediates in the final equation. 1. For the spontaneous reaction in water: Re(HzO)z + 2 KCN →Re(CN)z2 + 2K*(aq) + 2 H2O The postulate mechanism is where all species are in aqueous phase k1 Re(H₂O)2 + CN- Re(H₂O)(CN) + H₂O equilibrium Re(H₂O)(CN) + CN-I2 Re(H₂O)(CN)2-² Re(H2O)(CN)2243 Re(CN)22 + H2O k2 slow fast
Can experimentally determined differential rate laws contain the concentration of intermediates?
In a study of the rearrangement of ammonium cyanate to urea in aqueous solution at 50 °CNH4NCO(aq)(NH2)2CO(aq)the following data were obtained: [NH4NCO], M 0.780 0.390 0.195 9.75×10-2 minutes 0 131 393 918 Hint: It is not necessary to graph these data.(1)The observed half life for this reaction when the starting concentration is 0.780 M is______ min and when the starting concentration is 0.390 M is ______min.(2)The average (1/[NH4NCO]) / t from t = 0 min to t = 131 min is______ M-1 min-1.The average (1/[NH4NCO]) / t from t = 131 min to t = 393 min is_____ M-1 min-1.(3)Based on these data, the rate constant for this _______ (zerofirstsecond) order reaction is M-1 min-1. fill in the blanks

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