Energy to sublime Na(s) = 109.0 kJ/molElectron affinity of Cl(g) = -349.0 kJ/molFirst ionization energy of Na(g) = 495.0 kJ/molBond energy of Cl2(g) = 240.0 kJ/molΔHrxn for Na(s) + 1/2 Cl2(g) → NaCl(s) = -411.2 kJ/mol Determine the lattice energy of NaCl(s), using the data provided.
Energy to sublime Na(s) = 109.0 kJ/molElectron affinity of Cl(g) = -349.0 kJ/molFirst ionization energy of Na(g) = 495.0 kJ/molBond energy of Cl2(g) = 240.0 kJ/molΔHrxn for Na(s) + 1/2 Cl2(g) → NaCl(s) = -411.2 kJ/mol Determine the lattice energy of NaCl(s), using the data provided.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Energy to sublime Na(s) = 109.0 kJ/mol
Electron affinity of Cl(g) = -349.0 kJ/mol
First ionization energy of Na(g) = 495.0 kJ/mol
Bond energy of Cl2(g) = 240.0 kJ/mol
ΔHrxn for Na(s) + 1/2 Cl2(g) → NaCl(s) = -411.2 kJ/mol
Electron affinity of Cl(g) = -349.0 kJ/mol
First ionization energy of Na(g) = 495.0 kJ/mol
Bond energy of Cl2(g) = 240.0 kJ/mol
ΔHrxn for Na(s) + 1/2 Cl2(g) → NaCl(s) = -411.2 kJ/mol
Determine the lattice energy of NaCl(s), using the data provided.
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