At 20.0 °C, the vapor pressure of cyclohexane, a nonpolar hydrocarbon, is 66.9 torr and that of toluene, a hydrocarbon related to benzene, is 21.1 torr. Calculate the expected vapor pressure of a mixture of cyclohexane and toluene that consists of 124 grams of each liquid. Ptotal= i torr

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At 20.0 °C, the vapor pressure of cyclohexane, a nonpolar hydrocarbon, is 66.9 torr and that of toluene, a hydrocarbon related to
benzene, is 21.1 torr. Calculate the expected vapor pressure of a mixture of cyclohexane and toluene that consists of 124 grams of
each liquid.
Ptotal=
torr
Transcribed Image Text:At 20.0 °C, the vapor pressure of cyclohexane, a nonpolar hydrocarbon, is 66.9 torr and that of toluene, a hydrocarbon related to benzene, is 21.1 torr. Calculate the expected vapor pressure of a mixture of cyclohexane and toluene that consists of 124 grams of each liquid. Ptotal= torr
Expert Solution
Step 1

Raoult's Law states that vapor pressure of a solution formed by volatile solute and volatile solvent is as follows

                Ptotal=x1P1o+x2P2oHere, x1 is mole fraction of first component           P1o is the vapor pressure first component in pure state           x2 is mole fraction of second component           P2o is the vapor pressure second component in pure state

Here vapor pressure of pure cyclohexaneP1o is 66.9 torr and vapor pressure of pure tolueneP2o is 21.1 torr.

Amount of each component is 124 grams.

We have to find total pressure of the solution

Molar mass of cyclohexane is 84.16 g/mol

Molar mass of toluene is 92.14 g/mol

  

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