Empirical Formula Proof for C₂H302, a compound containing 57.838% carbon, 3.641% hydrogen, and 38.521% oxygen : CARBON 57.838% 79.887% 27.293% 40.002% ASSUME A 100 g SAMPLE 57.838% of 100: 0.57838 100 = 57.838 g C 3.641% of 100: 0.03641100 = 3.641 g H 38.521% of 100: 0.38521100= 38.521 g 0 Show the empirical formula proof for any other compound listed in the table provided: Percent Composition HYDROGEN 3.6405% 20.113% 6.7142% OXYGEN 38.521% 72.711% 53.284% Empirical Formula 57.838 g C x CONVERT EACH TO MOLES USING MOLAR MASS OF EACH ELEMENT 1 mole C= 4.8154 moles C 12.011 g C 3.641 g H x 1 mole H = 1.008 g H 38.521 g 0 x 1 mole 0 2.4077 moles O 15.999 g O C₂H₂O₂ CH₂ CO₂ CH₂O Molecular Formula C₂H₂O₁ C₂H₂ CO₂ C₂H₂O 3.6121 moles H DIVIDE ALL MOLES BY THE SMALLEST MOLE AMOUNT 4.8154 moles C/ 2.4077= 2 3.6121 moles H/2.4077 = 1.5 2.4077 moles O/2.4077= 1 C₂H₁.501 MULTIPLY & ROUND SUBSCRIPTS TO ENSURE WHOLE NUMBERS AS NECESSARY C₂H₁.50₁ I C₂H₂O₂ x 2
Empirical Formula Proof for C₂H302, a compound containing 57.838% carbon, 3.641% hydrogen, and 38.521% oxygen : CARBON 57.838% 79.887% 27.293% 40.002% ASSUME A 100 g SAMPLE 57.838% of 100: 0.57838 100 = 57.838 g C 3.641% of 100: 0.03641100 = 3.641 g H 38.521% of 100: 0.38521100= 38.521 g 0 Show the empirical formula proof for any other compound listed in the table provided: Percent Composition HYDROGEN 3.6405% 20.113% 6.7142% OXYGEN 38.521% 72.711% 53.284% Empirical Formula 57.838 g C x CONVERT EACH TO MOLES USING MOLAR MASS OF EACH ELEMENT 1 mole C= 4.8154 moles C 12.011 g C 3.641 g H x 1 mole H = 1.008 g H 38.521 g 0 x 1 mole 0 2.4077 moles O 15.999 g O C₂H₂O₂ CH₂ CO₂ CH₂O Molecular Formula C₂H₂O₁ C₂H₂ CO₂ C₂H₂O 3.6121 moles H DIVIDE ALL MOLES BY THE SMALLEST MOLE AMOUNT 4.8154 moles C/ 2.4077= 2 3.6121 moles H/2.4077 = 1.5 2.4077 moles O/2.4077= 1 C₂H₁.501 MULTIPLY & ROUND SUBSCRIPTS TO ENSURE WHOLE NUMBERS AS NECESSARY C₂H₁.50₁ I C₂H₂O₂ x 2
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
Section3.9: Composition And Empirical Formulas
Problem 3.21CE: Phenol is a compound of carbon, hydrogen, and oxygen used commonly as a disinfectant. Combustion of...
Related questions
Question
Solve like the exmaple
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 4 steps with 1 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781337399074
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781337399074
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
Introductory Chemistry: A Foundation
Chemistry
ISBN:
9781337399425
Author:
Steven S. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781133949640
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning