Elemental analysis determined unknown Compound G to contain 40.0 % carbon, 6.7 % hydrogen. Compound G had an M+ = 60 m/z on its MS. Its IR displayed three absorbances: strong at 1710, strong below 3000, and broad from 2500 to 3500. The proton NMR showed an absorbance at 1.7 ppm (lowest whole number ratio of H =3), and an absorbance at 11.5 ppm (lowest whole number ratio of H = 1). Compound G was able to turn blue litmus paper red, and neutralize a base. What is Compound G? O CH3CO2H O Formaldehyde о но C CH2 HO O CHy(OH)CHO O CHIOH CH(OH)

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Elemental analysis determined unknown Compound G to contain 40.0 % carbon, 6.7 % hydrogen. Compound G
had an M+ = 60 m/z on its MS.
Its IR displayed three absorbances: strong at 1710, strong below 3000, and broad from 2500 to 3500.
The proton NMR showed an absorbance at 1.7 ppm (lowest whole number ratio of H =3), and an absorbance at
11.5 ppm (lowest whole number ratio of H = 1).
Compound G was able to turn blue litmus paper red, and neutralize a base. What is Compound G?
O CH3CO2H
O Formaldehyde
O HO
C CH2
HO
O CHy(OH)CHO
O CHOHHCH(OH)
Transcribed Image Text:Elemental analysis determined unknown Compound G to contain 40.0 % carbon, 6.7 % hydrogen. Compound G had an M+ = 60 m/z on its MS. Its IR displayed three absorbances: strong at 1710, strong below 3000, and broad from 2500 to 3500. The proton NMR showed an absorbance at 1.7 ppm (lowest whole number ratio of H =3), and an absorbance at 11.5 ppm (lowest whole number ratio of H = 1). Compound G was able to turn blue litmus paper red, and neutralize a base. What is Compound G? O CH3CO2H O Formaldehyde O HO C CH2 HO O CHy(OH)CHO O CHOHHCH(OH)
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