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13.14 A compound with molecular formula C5H₁0O₂ has the following NMR spectrum. Determine the number of protons giving rise to the peak at 2.0 ppm. 5.0 6.33 4.5 4.0 3.5 3.0 2.5 Integration Values 2.0 1.5 1.0 19.4 37.9 0.5 ppm

13.14 A compound with molecular formula C5H₁0O₂ has the following NMR spectrum. Determine the number of protons giving rise to the peak at 2.0 ppm. 5.0 6.33 4.5 4.0 3.5 3.0 2.5 Integration Values 2.0 1.5 1.0 19.4 37.9 0.5 ppm

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Determine the number of protons giving rise to the peak at 2.0 ppm.

**Title: Analyzing NMR Spectrum for Proton Determination** **Section 13.14: Understanding NMR Spectrum** We have a compound with the molecular formula C₅H₁₀O₂. The provided NMR spectrum helps us determine the number of protons giving rise to the peak at 2.0 ppm. **Detailed Explanation of the NMR Spectrum:** - **X-Axis (ppm):** The horizontal axis represents the chemical shift in parts per million (ppm). It ranges from 5.5 to 0.0 ppm. - **Peaks:** - A small peak appears around 4.1 ppm. - A significant peak is located at 2.0 ppm. - Another large peak is seen around 1.1 ppm. - **Integration Values:** - The integration values corresponding to each peak are crucial as they indicate the relative number of protons. - The integrals given in the spectrum are: - Around 4.1 ppm: 6.33 - At 2.0 ppm: 19.4 - Around 1.1 ppm: 37.9 **Task:** - Determine the number of protons corresponding to the peak at 2.0 ppm. **Concept Reminder:** The integral values represent relative areas under each peak. The ratio of these integrals helps calculate the number of protons. You can divide each integral by the smallest integral value to simplify the ratios. **Key Questions:** - What is the ratio of the integrals provided? - How many hydrogen atoms are present in total within the molecule? Use this information to deduce the distribution of hydrogen atoms in the compound based on the given integrals and solve the provided problem.
Transcribed Image Text:**Title: Analyzing NMR Spectrum for Proton Determination** **Section 13.14: Understanding NMR Spectrum** We have a compound with the molecular formula C₅H₁₀O₂. The provided NMR spectrum helps us determine the number of protons giving rise to the peak at 2.0 ppm. **Detailed Explanation of the NMR Spectrum:** - **X-Axis (ppm):** The horizontal axis represents the chemical shift in parts per million (ppm). It ranges from 5.5 to 0.0 ppm. - **Peaks:** - A small peak appears around 4.1 ppm. - A significant peak is located at 2.0 ppm. - Another large peak is seen around 1.1 ppm. - **Integration Values:** - The integration values corresponding to each peak are crucial as they indicate the relative number of protons. - The integrals given in the spectrum are: - Around 4.1 ppm: 6.33 - At 2.0 ppm: 19.4 - Around 1.1 ppm: 37.9 **Task:** - Determine the number of protons corresponding to the peak at 2.0 ppm. **Concept Reminder:** The integral values represent relative areas under each peak. The ratio of these integrals helps calculate the number of protons. You can divide each integral by the smallest integral value to simplify the ratios. **Key Questions:** - What is the ratio of the integrals provided? - How many hydrogen atoms are present in total within the molecule? Use this information to deduce the distribution of hydrogen atoms in the compound based on the given integrals and solve the provided problem.
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