Total number of stereoisomers possible for the followingcompounds isHINT:a. 4How many possible stereoisomers?How do we know how many stereoisomers are possible for a given structure? There is actually a straightforward way to figure this out. All we need to do iscount the number of chiral centers and stereogenic alkene groups, the use this following rule:number of stereoisomeric forms = 2"... where n = the number of chiral centers plus the number of stereogenic alkene groupsb. 2Consider for example a molecule with two chiral centers and one stereogenic alkene. By the rule stated above, we know right away that there must be eightpossible stereoisomers.terminal alkeneOHstereogenic alkeneC. 8OHd. 3OHchiral centerHOOH32 = 8Tnonstereogenic alkenes (cannot be labelled E or Z)← Predict the 1H shifts of the protons on the labeled carbons of the following chemical structure:OHNH₂aNH(1) 5.40, H(2)=5.46b. H(1)=5.46, H(2)=5.40c. H(1) 6.64, H(2)=6.60d. H(1)=5.54, H(2)=5.58e. H(1) 6.40, H(2)=6.44

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Total number of stereoisomers possible for the following compounds is HINT: How many possible stereoisomers? How do we know how many stereoisomers are possible for a given structure? There is actually a straightforward way to figure this out. All we need to do i count the number of chiral centers and stereogenic alkene groups, the use this following rule: number of stereoisomeric forms = 2" ... where n = the number of chiral centers plus the number of stereogenic alkene groups a. 4 Consider for example a molecule with two chiral centers and one stereogenic alkene. By the rule stated above, we know right away that there must be eigh possible stereoisomers. terminal alkene stereogenic alkene OH b. 2 OH C. 8 d. 3 OH HO chiral center OH = 8 nonstereogenic alkenes (cannot be labelled E or Z)

Total number of stereoisomers possible for the following compounds is HINT: How many possible stereoisomers? How do we know how many stereoisomers are possible for a given structure? There is actually a straightforward way to figure this out. All we need to do i count the number of chiral centers and stereogenic alkene groups, the use this following rule: number of stereoisomeric forms = 2" ... where n = the number of chiral centers plus the number of stereogenic alkene groups a. 4 Consider for example a molecule with two chiral centers and one stereogenic alkene. By the rule stated above, we know right away that there must be eigh possible stereoisomers. terminal alkene stereogenic alkene OH b. 2 OH C. 8 d. 3 OH HO chiral center OH = 8 nonstereogenic alkenes (cannot be labelled E or Z)

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter3: Organic Compounds: Alkanes And Their Stereochemistry

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Problem 54AP: In the next chapter we'll look at cycloalkanesâ€”saturated cyclic hydrocarbonsâ€”and weâ€™ll see...

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Concept explainers

Alkanes and Cycloalkanes

Alkanes are saturated organic compounds which are made up of C and H atoms. Alkanes have the general formula of CnH2n+2. Alkane contains sp3 hybridized carbon atoms with four sigmas (σ) bonds & every hydrogen atom is connected with one of the carbon atoms. The size of the alkane could be determined by the number of carbon atoms located in it.

Question

Total number of stereoisomers possible for the following
compounds is
HINT:
a. 4
How many possible stereoisomers?
How do we know how many stereoisomers are possible for a given structure? There is actually a straightforward way to figure this out. All we need to do is
count the number of chiral centers and stereogenic alkene groups, the use this following rule:
number of stereoisomeric forms = 2"
... where n = the number of chiral centers plus the number of stereogenic alkene groups
b. 2
Consider for example a molecule with two chiral centers and one stereogenic alkene. By the rule stated above, we know right away that there must be eight
possible stereoisomers.
terminal alkene
OH
stereogenic alkene
C. 8
OH
d. 3
OH
chiral center
HO
OH
3
2 = 8
T
nonstereogenic alkenes (cannot be labelled E or Z)
←

Predict the 1H shifts of the protons on the labeled carbons of the following chemical structure:
OH
NH₂
a
N
H(1) 5.40, H(2)=5.46
b. H(1)=5.46, H(2)=5.40
c. H(1) 6.64, H(2)=6.60
d. H(1)=5.54, H(2)=5.58
e. H(1) 6.40, H(2)=6.44

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