Total number of stereoisomers possible for the followingcompounds isHINT:a. 4How many possible stereoisomers?How do we know how many stereoisomers are possible for a given structure? There is actually a straightforward way to figure this out. All we need to do iscount the number of chiral centers and stereogenic alkene groups, the use this following rule:number of stereoisomeric forms = 2"... where n = the number of chiral centers plus the number of stereogenic alkene groupsb. 2Consider for example a molecule with two chiral centers and one stereogenic alkene. By the rule stated above, we know right away that there must be eightpossible stereoisomers.terminal alkeneOHstereogenic alkeneC. 8OHd. 3OHchiral centerHOOH32 = 8Tnonstereogenic alkenes (cannot be labelled E or Z)← Predict the 1H shifts of the protons on the labeled carbons of the following chemical structure:OHNH₂aNH(1) 5.40, H(2)=5.46b. H(1)=5.46, H(2)=5.40c. H(1) 6.64, H(2)=6.60d. H(1)=5.54, H(2)=5.58e. H(1) 6.40, H(2)=6.44

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Total number of stereoisomers possible for the following compounds is HINT: How many possible stereoisomers? How do we know how many stereoisomers are possible for a given structure? There is actually a straightforward way to figure this out. All we need to do i count the number of chiral centers and stereogenic alkene groups, the use this following rule: number of stereoisomeric forms = 2" ... where n = the number of chiral centers plus the number of stereogenic alkene groups a. 4 Consider for example a molecule with two chiral centers and one stereogenic alkene. By the rule stated above, we know right away that there must be eigh possible stereoisomers. terminal alkene stereogenic alkene OH b. 2 OH C. 8 d. 3 OH HO chiral center OH = 8 nonstereogenic alkenes (cannot be labelled E or Z)

Total number of stereoisomers possible for the following compounds is HINT: How many possible stereoisomers? How do we know how many stereoisomers are possible for a given structure? There is actually a straightforward way to figure this out. All we need to do i count the number of chiral centers and stereogenic alkene groups, the use this following rule: number of stereoisomeric forms = 2" ... where n = the number of chiral centers plus the number of stereogenic alkene groups a. 4 Consider for example a molecule with two chiral centers and one stereogenic alkene. By the rule stated above, we know right away that there must be eigh possible stereoisomers. terminal alkene stereogenic alkene OH b. 2 OH C. 8 d. 3 OH HO chiral center OH = 8 nonstereogenic alkenes (cannot be labelled E or Z)

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter3: Organic Compounds: Alkanes And Their Stereochemistry

Section3.SE: Something Extra

Problem 54AP: In the next chapter we'll look at cycloalkanesâ€”saturated cyclic hydrocarbonsâ€”and weâ€™ll see...

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In the next chapter we'll look at cycloalkanesâ€”saturated cyclic hydrocarbonsâ€”and weâ€™ll see that the molecules generally adopt puckered, nonplanar conformations. Cyclohexane, for instance, has a puckered shape like a lounge chair rather than a flat shape. Why?
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Total number of stereoisomers possible for the following compounds is HINT: a. 4 How many possible stereoisomers? How do we know how many stereoisomers are possible for a given structure? There is actually a straightforward way to figure this out. All we need to do is count the number of chiral centers and stereogenic alkene groups, the use this following rule: number of stereoisomeric forms = 2" ... where n = the number of chiral centers plus the number of stereogenic alkene groups b. 2 Consider for example a molecule with two chiral centers and one stereogenic alkene. By the rule stated above, we know right away that there must be eight possible stereoisomers. terminal alkene OH stereogenic alkene C. 8 OH d. 3 OH chiral center HO OH 3 2 = 8 T nonstereogenic alkenes (cannot be labelled E or Z) ←
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Hello, I was reading an answer from the book Organic Chemistry by Brown et al. The question is 2.51 "Draw alternative chair conformations for each substituted cyclohexane and state which chair is more stable." There are then 4 cyclohexanes (labeled a-d). For the "a" cyclohexane, the substituents are arranged as a combination of axial and equatorial in both chair conformations. However, for the "b," "c," and "d," cyclohexanes one chair has only equatorial substituents, and the other chair has only axial substituents. Why is the "a" chair conformation different? https://www.bartleby.com/solution-answer/chapter-2-problem-251p-organic-chemistry-8th-edition/9781305580350/draw-alternative-chair-conformations-for-each-substituted-cyclohexane-and-state-which-chair-is-more/4532cd91-c341-11e9-8385-02ee952b546e