Electrons passes undeviated through crossed electric and magnetic fields. If E = 5 x 104 N/c and B = 4 x 10-4 Wb/m² find the velocity of electrons.
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- F.j = (-e)(-v,k) × (B,i + B.k) ev Bzj. Solving for B gives F. Br 8.50x10 16 N = 1.13 T. Therefore B = 1.13 Ti – 0.772 Tk. The magnitude o A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.70 km/s in the +x-direction experiences a force of 2.10x10-16 N in the +y- direction, and an electron moving at 4.70 km/s in the eve (1.60x10 19 C)(4700 m/s) is B = VB? + B = (1.13 T)² + (-0.772 T)² = 1.37 T. -z-direction experiences a force of 8.50x10-16 N in the +y-direction. Part B For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Magnetic force on a proton. What is the direction of the magnetic field? (in the xz-plane) Express your answer in degrees. 0 = 60.59 ° from the -z-direction to the +x-direction Submit Previous Answers Request Answer X Incorrect; Try Again; 9 attempts remaining12.57×10-7 Tesla is not a valid option of the answers available to choose.In a nuclear experiment a photon with kinetic energy 6.0 MeV moves in a circular path in a uniform magnetic field. If the magnetic field is B= 1.7 T what is the radius of the orbit?
- The Hall affect is used to measure the carrier density of a thin sheet of electrons. When a current of 80.0 µA flows through the length of the electron sheet, which is 1.2-mm long, 0.27- mm wide and 12-nm thick, a magnetic field perpendicular to the sheet produces a potential difference of 0.53 mV across the width of the sheet. If the carrier density in the electron sheet is 6.74 x 1025 m-3, what is the magnitude of the magnetic field?4+ 71. In Millikan's experiment, a potential difference of 2.0 is applied between the two plates, which are 8 mm apart, to balance an oil drop of mass 4.9 × 10-4 kg. Calculate the number of elementary charges on the drop (g = 10 m/s²). (7.6) m 106 mlo enters a 0.800 T. (8.2) TI (a) Determine the magnitude of the magnetic 101 exerted on the proton. (h) Dorcriho th tolro tho proton as it stays OFF /NO 2nd F CA MODE STAT VAR ALPHA SNI DEL SET UP RESET arc hypNOT sin1AND cos OR tan XOR DRGXNOR dhy sin COS DRG D 10 E A uj DEG STO Exp abc D°M'S DATA CD. -xy oy RANDOM re 6 sx*nPr ox CHEX CBINr ju 5. 2. 1. ANS 3. DECElectrons enter a magnetic field traveling at v, = vỹ. The constant, uniform magnetic field B = 0.75 2 T acts as a filter curving the electrons to a small gap that only allows specific electron energies. The source of electrons enters the filter as a beam that is 15 micrometers in diameter and have a range of energies from 5-25 meV. The filter redirects the beam, as pictured, to the right v = và but does not speed them up. If the filter is to further narrow the range of energies from 5-25 meV to 10-12 meV, find the dimensions of the gap. In the picture, calculate ymin and ymer, both of which can be assumed to be equal to the radius of the paths taken within the magnetic field. %3D The beam being focused to 15 um at the start can be assumed to be a point source and take circular paths within the magnetic field. Outgoing "Filtered" Electrons Blocked Electrons -不: Y Vma Incoming Electrons