F.j (-e)(-v.k) x (Bi+B.k) = ev.B.j. Solving for B, gives F, B2 8.50x 10 16 N (1.60x 10 19 C)(4700 m/s) B + B = -= 1.13 T. Therefore B= 1.13 Ti - 0.772 Tk. The magnitude o A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.70 km/s in the +x-direction experiences a force of 2.10x10-16 N in the +y- direction, and an electron moving at 4.70 km/s in the -z-direction experiences a force of 8.50x10-16 N in the +y-direction. %3D eve is B = V(1.13 T)2 + (-0.772 T)² = 1.37 T. Part B For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Magnetic force on a proton. What is the direction of the magnetic field? (in the az-plane) Express your answer in degrees. V AE ? 0 = 60.59 from the -z-direction to the +x-direction Submit Previous Answers Request Answer
F.j (-e)(-v.k) x (Bi+B.k) = ev.B.j. Solving for B, gives F, B2 8.50x 10 16 N (1.60x 10 19 C)(4700 m/s) B + B = -= 1.13 T. Therefore B= 1.13 Ti - 0.772 Tk. The magnitude o A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.70 km/s in the +x-direction experiences a force of 2.10x10-16 N in the +y- direction, and an electron moving at 4.70 km/s in the -z-direction experiences a force of 8.50x10-16 N in the +y-direction. %3D eve is B = V(1.13 T)2 + (-0.772 T)² = 1.37 T. Part B For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Magnetic force on a proton. What is the direction of the magnetic field? (in the az-plane) Express your answer in degrees. V AE ? 0 = 60.59 from the -z-direction to the +x-direction Submit Previous Answers Request Answer
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![F.j = (-e)(-v,k) × (B,i + B.k)
ev Bzj. Solving for B gives
F.
Br
8.50x10 16 N
= 1.13 T. Therefore B = 1.13 Ti – 0.772 Tk. The magnitude o
A group of particles is traveling in a magnetic field of
unknown magnitude and direction. You observe that a
proton moving at 1.70 km/s in the +x-direction
experiences a force of 2.10x10-16 N in the +y-
direction, and an electron moving at 4.70 km/s in the
eve
(1.60x10 19 C)(4700 m/s)
is B = VB? + B =
(1.13 T)² + (-0.772 T)² = 1.37 T.
-z-direction experiences a force of 8.50x10-16 N in
the +y-direction.
Part B
For related problem-solving tips and strategies, you
may want to view a Video Tutor Solution of Magnetic
force on a proton.
What is the direction of the magnetic field? (in the xz-plane)
Express your answer in degrees.
0 = 60.59
° from the -z-direction to the +x-direction
Submit
Previous Answers Request Answer
X Incorrect; Try Again; 9 attempts remaining](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5a23ec30-1893-43e5-a88b-b0881109ea21%2Fba030285-7e6f-428c-8f3a-735d1567342c%2Fc3uqwsf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:F.j = (-e)(-v,k) × (B,i + B.k)
ev Bzj. Solving for B gives
F.
Br
8.50x10 16 N
= 1.13 T. Therefore B = 1.13 Ti – 0.772 Tk. The magnitude o
A group of particles is traveling in a magnetic field of
unknown magnitude and direction. You observe that a
proton moving at 1.70 km/s in the +x-direction
experiences a force of 2.10x10-16 N in the +y-
direction, and an electron moving at 4.70 km/s in the
eve
(1.60x10 19 C)(4700 m/s)
is B = VB? + B =
(1.13 T)² + (-0.772 T)² = 1.37 T.
-z-direction experiences a force of 8.50x10-16 N in
the +y-direction.
Part B
For related problem-solving tips and strategies, you
may want to view a Video Tutor Solution of Magnetic
force on a proton.
What is the direction of the magnetic field? (in the xz-plane)
Express your answer in degrees.
0 = 60.59
° from the -z-direction to the +x-direction
Submit
Previous Answers Request Answer
X Incorrect; Try Again; 9 attempts remaining
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