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F.j (-e)(-v.k) x (Bi+B.k) = ev.B.j. Solving for B, gives F, B2 8.50x 10 16 N (1.60x 10 19 C)(4700 m/s) B + B = -= 1.13 T. Therefore B= 1.13 Ti - 0.772 Tk. The magnitude o A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.70 km/s in the +x-direction experiences a force of 2.10x10-16 N in the +y- direction, and an electron moving at 4.70 km/s in the -z-direction experiences a force of 8.50x10-16 N in the +y-direction. %3D eve is B = V(1.13 T)2 + (-0.772 T)² = 1.37 T. Part B For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Magnetic force on a proton. What is the direction of the magnetic field? (in the az-plane) Express your answer in degrees. V AE ? 0 = 60.59 from the -z-direction to the +x-direction Submit Previous Answers Request Answer

F.j (-e)(-v.k) x (Bi+B.k) = ev.B.j. Solving for B, gives F, B2 8.50x 10 16 N (1.60x 10 19 C)(4700 m/s) B + B = -= 1.13 T. Therefore B= 1.13 Ti - 0.772 Tk. The magnitude o A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.70 km/s in the +x-direction experiences a force of 2.10x10-16 N in the +y- direction, and an electron moving at 4.70 km/s in the -z-direction experiences a force of 8.50x10-16 N in the +y-direction. %3D eve is B = V(1.13 T)2 + (-0.772 T)² = 1.37 T. Part B For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Magnetic force on a proton. What is the direction of the magnetic field? (in the az-plane) Express your answer in degrees. V AE ? 0 = 60.59 from the -z-direction to the +x-direction Submit Previous Answers Request Answer

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F.j = (-e)(-v,k) × (B,i + B.k) ev Bzj. Solving for B gives F. Br 8.50x10 16 N = 1.13 T. Therefore B = 1.13 Ti – 0.772 Tk. The magnitude o A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.70 km/s in the +x-direction experiences a force of 2.10x10-16 N in the +y- direction, and an electron moving at 4.70 km/s in the eve (1.60x10 19 C)(4700 m/s) is B = VB? + B = (1.13 T)² + (-0.772 T)² = 1.37 T. -z-direction experiences a force of 8.50x10-16 N in the +y-direction. Part B For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Magnetic force on a proton. What is the direction of the magnetic field? (in the xz-plane) Express your answer in degrees. 0 = 60.59 ° from the -z-direction to the +x-direction Submit Previous Answers Request Answer X Incorrect; Try Again; 9 attempts remaining
Transcribed Image Text:F.j = (-e)(-v,k) × (B,i + B.k) ev Bzj. Solving for B gives F. Br 8.50x10 16 N = 1.13 T. Therefore B = 1.13 Ti – 0.772 Tk. The magnitude o A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.70 km/s in the +x-direction experiences a force of 2.10x10-16 N in the +y- direction, and an electron moving at 4.70 km/s in the eve (1.60x10 19 C)(4700 m/s) is B = VB? + B = (1.13 T)² + (-0.772 T)² = 1.37 T. -z-direction experiences a force of 8.50x10-16 N in the +y-direction. Part B For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Magnetic force on a proton. What is the direction of the magnetic field? (in the xz-plane) Express your answer in degrees. 0 = 60.59 ° from the -z-direction to the +x-direction Submit Previous Answers Request Answer X Incorrect; Try Again; 9 attempts remaining
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