Electrons are emitted from the surface of a metal when it's exposed to light. This is called the photoelectric effect. Each metal has a certain threshold frequency of light, below which nothing happens. Right at this threshold frequency, an electron is emitted. Above this frequency, the electron is emitted and the extra energy is Here are some data collected on a sample of cesium exposed to various energies of light. Light energy (eV) Electron emitted? Electron KE (eV) 3.87 no transferred to the electron. 3.88 no The equation for this phenomenon is 3.89 yes KE= hv – hvo 3.90 yes 0.01 where KE is the kinetic energy of the emitted electron, h = 6.63 × 10–34 J.s is Planck's constant, v is the frequency of the light, and vo is the threshold frequency of the metal. 3.91 yes 0.02 *Note that 1 eV (electron volt) = 1.60 × 10-19 J. Also, since E = hv, the equation can also be Part A written as KE= E – þ What is the threshold frequency vo of cesium? where E is the energy of the light and o is the binding energy of the electron in the metal. Express your answer numerically in hertz. • View Available Hint(s) ΑΣφ ? Vo = Hz

Electrons are emitted from the surface of a metal when it's exposed to light. This is called the photoelectric effect. Each metal has a certain threshold frequency of light, below which nothing happens. Right at this threshold frequency, an electron is emitted. Above this frequency, the electron is emitted and the extra energy is Here are some data collected on a sample of cesium exposed to various energies of light. Light energy (eV) Electron emitted? Electron KE (eV) 3.87 no transferred to the electron. 3.88 no The equation for this phenomenon is 3.89 yes KE= hv – hvo 3.90 yes 0.01 where KE is the kinetic energy of the emitted electron, h = 6.63 × 10–34 J.s is Planck's constant, v is the frequency of the light, and vo is the threshold frequency of the metal. 3.91 yes 0.02 *Note that 1 eV (electron volt) = 1.60 × 10-19 J. Also, since E = hv, the equation can also be Part A written as KE= E – þ What is the threshold frequency vo of cesium? where E is the energy of the light and o is the binding energy of the electron in the metal. Express your answer numerically in hertz. • View Available Hint(s) ΑΣφ ? Vo = Hz

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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