egion is given by the equation E=(axn − b)i, where a = 12 N/(C⋅mn), b = 5 N/C and n = 6. Calculate the electric potential difference (ΔV = V2 − V1), in volts, between the points x2 = 1.6 m and x1 = 0.65 m, i.e., ΔV = V(x2) − V(x1). ΔV =
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ΔV = |
Given
a = 12 N/C.mn
b= 5 N/C
n=6
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- Given cylindrical capacitor of length = 61.4044 m where the radius of the inner plate is R₁ = 6.2696 m and the outer plate is R2 = 40.7022 m. The capacitor is charged with charge Q = 3 × 10-4 C Three cylindrical conductors of width d= 0.56 m are inserted into the capacitor: Two cylindrical conductors inserted concentrically in between the capacitor plates and the third conductor is inserted concentrically inside the first plate, as seen in the figure below: Top view (a) R₂ Given that a = 3.2696 m b = 11.2696 m c = 14.2696 m How much energy (in Joule) is lost in the process? Top view (b)In nuclear fission, a nucleus splits roughly in half. a)What is the potential (in V) 4.50 ✕ 10−14 m from a fragment that has 50 protons in it? and b) What is the potential energy in MeV of a similarly charged fragment at this distance?A graph as been drawn between 1 over u and 1 over v from the above tabulated values. 1/u Vs 1/v Graph 0.100 0.095 Scale value: X axis Y axis 0.090 1 unit =0.005 cm 1 unit = 0.005 cm 0.08S 0.080 SLOO 0.070 0.065 0.060 0.055 0.050 0.045 0.040 0.035 0.030 0.025 0.020 0.015 0.005 0.000 a.000 a00s a010 a01s ao0 a02s a030 a0s a040 a045 a.050 aoss a.060 004S ao0 a0s a080 a08s a090 a09s a100 1/u in cm-1 1) X intercept (Value of ) in (cm-1) 2) Yintercept (Value of ) in (cm-1) 3) Mean value of (cm-1) 4) Calculate f(cm)
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