Consider an electric potential defined by V(x,y,z)=12x2z+y [volts]. What is the magnitude of the electric field [in V/m] at (x,y,z)=(3.8,1.5,−7.7) m?
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Consider an electric potential defined by V(x,y,z)=12x2z+y [volts]. What is the magnitude of the electric field [in V/m] at (x,y,z)=(3.8,1.5,−7.7) m?
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- Please asapConsider a parallel-plate capacitor constructed of two square plates, 4.22 m on a side, separated by a distance 6.23 mm. If a charge of 2.85 nC is placed on one plate, with an equal but opposite charge on the other plate, find the electric field inside the capacitor. Answer in units of V/m.Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.32 cm. If the potential difference across the plates was 24.0 kV, find the magnitude of the electric field (in V/m) in the region between the plates.
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- The electric field strength between two parallel conducting plates separated by 4.20 cm is 6.40 ✕ 104 V/m. a) What is the potential difference between the plates (in kV)? and b)The plate with the lowest potential is taken to be at zero volts. What is the potential (in V) 1.40 cm from that plate (and 2.80 cm from the other)?Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.44 cm. If the potential difference across the plates was 29.5 kV, find the magnitude of the electric field (in V/m) in the region between the plates.The electric potential is given by the following expression: V(x, y, z) = x²yz + 2y²z, where V is in volts. Determine the electric field (magnitude and direction) at point (1, 1, 2).
- Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.54 cm. If the potential difference across the plates was 28.5 kV, find the magnitude of the electric field (in V/m) in the region between the plates.A parallel plate capacitor has a surface charge density of magnitude o = 0.00433 C/m² on each plate. A small sphere, charged to Q = 9.40 × 10-6 C and located between the plates, undergoes a displacement of magnitude d = 0.143 m. Refer to the figure, which is not drawn to scale. y +++++++ Using the symbols in the palette, not their numeric equivalents, enter an expression, in Cartesian unit-vector notation, for the electric field within the capacitor. If the displacement is from left to right, then how much work, in joules, is performed on the sphere by the electric field? At what speed, in meters per second, is the sphere moving when it completes the displacement if it starts from rest and its mass is 0.115 kg? XOver a certain region of space, the electric potential is V = 7x - 2x2y + 2yz2. Find the expression for the x component of the electric field over this region. (Use the following as necessary: x, y, and z.) Ex = Find the expression for the y component of the electric field over this region. Ey = Find the expression for the z component of the electric field over this region. Ez = What is the magnitude of the field at the point P, which has coordinates (7, 0, -7) m? N/C