Effect on Volume of HCl used if Solid Ca(OH)2 (s) Impurities Present because Improperly Filtered (explained using Le Chatelier's Principle) stress because neutralized by 0.0400 M added HCI shift result • presence of Ca(OH)2 (s) impurity allows an reaction to occur • as OH- (ag) ions in Ca(OH)2 (aq) solution are neutralized, equilibrim shifts to • more OH- (aq) ions are released from .... .Ca(OH)2 impurity, :: additional .is added to neutralize the extra OH- (aq) ions • Ca(OH)2 (s) impurity continues to release OH- (ag) ions until all solid Ca(OH)2 has • . the volume of HCI (aq) used to neutralize the solution is artificially and calculated K, of Ca(OH)2 is artificially (4 Kap Ca(OH)2 = * [Ca(OH)2 (aq)] determined is artificially

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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O The Importance of Filtering the Saturated Ca(OH)2 (aq) So No Solid Ca(OH)2 (s) is Present during the Titration
Ca(OH)2 (s)
Ca2+ (aq) + 2OH- (aq)
if solid not filtered out, an equilibrium can occur between the unfiltered
solid Ca(OH)2 and the aqueous Ca?• (aq) + 20H- (aq) ions
Neutralization (Titration) Reaction
If not properly
filtered. Ca(OH)2 (s)
present in solution
being titrated
Balanced eq: 2HCI(aq) + Ca(OH)2(aq) → CaCk(aq) + 2H20(1)
lonic eq: 2H*(aq) + 2CH(aq) + Ca2 (aq) + 20H-(aq) → Ca²•(aq) + 2CH(aq) + 2H2O (I)
Net lonic eq: 2H•(aq) + 2OH-(aq) → 2H¿O (I)
Effect on Volume of HCI used if Solid Ca(OH)2 (s) Impurities Present because Improperly Filtered (explained using Le Chatelier's Principle)
shift
stress
because neutralized by 0.0400 M added HCI
reaction to occur
result
• presence of Ca(OH)2 (s) impurity allows an
• as OH- (aq) ions in
Ca(OH)2 (aq) solution are neutralized, equilibrim shifts to
is added to
• more OH- (aq) ions are released from
.. .Ca(OH)2 impurity, :: additional
neutralize the extra OH- (aq) ions
• Ca(OH)2 (s) impurity continues to release OH- (ag) ions until all solid Ca(OH)2 has
• : the volume of HCI (aq) used to neutralize the solution is artificially
and calculated Ks, of Ca(OH)2 is artificially
(4 Ksp Ca(OH)2 =
. : [Ca(OH)2 (aq)] determined is artificially
Transcribed Image Text:O The Importance of Filtering the Saturated Ca(OH)2 (aq) So No Solid Ca(OH)2 (s) is Present during the Titration Ca(OH)2 (s) Ca2+ (aq) + 2OH- (aq) if solid not filtered out, an equilibrium can occur between the unfiltered solid Ca(OH)2 and the aqueous Ca?• (aq) + 20H- (aq) ions Neutralization (Titration) Reaction If not properly filtered. Ca(OH)2 (s) present in solution being titrated Balanced eq: 2HCI(aq) + Ca(OH)2(aq) → CaCk(aq) + 2H20(1) lonic eq: 2H*(aq) + 2CH(aq) + Ca2 (aq) + 20H-(aq) → Ca²•(aq) + 2CH(aq) + 2H2O (I) Net lonic eq: 2H•(aq) + 2OH-(aq) → 2H¿O (I) Effect on Volume of HCI used if Solid Ca(OH)2 (s) Impurities Present because Improperly Filtered (explained using Le Chatelier's Principle) shift stress because neutralized by 0.0400 M added HCI reaction to occur result • presence of Ca(OH)2 (s) impurity allows an • as OH- (aq) ions in Ca(OH)2 (aq) solution are neutralized, equilibrim shifts to is added to • more OH- (aq) ions are released from .. .Ca(OH)2 impurity, :: additional neutralize the extra OH- (aq) ions • Ca(OH)2 (s) impurity continues to release OH- (ag) ions until all solid Ca(OH)2 has • : the volume of HCI (aq) used to neutralize the solution is artificially and calculated Ks, of Ca(OH)2 is artificially (4 Ksp Ca(OH)2 = . : [Ca(OH)2 (aq)] determined is artificially
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