To 200.0 ml of a solution of Al(NO3)3 with concentration (2.000x10^-3) mol L-1,(3.0x10^2) ml of (1.00x10^-1) mol L-1 NaF is added. Determine the concentration offree aluminum ions after equilibrium has been established.(K+(AIF63-) = 7.0 x 1019)Note: Your answer is assumed to be reduced to the highest power possible.Your Answer:x10Answerunits

Step 1: Initial Concentrations and VolumesInitial concentration of Al(NO3)3 (Alinit)=…

Answered: To 200.0 ml of a solution of Al(NO3)3…

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter15: Complex Ion And Precipitation Equilibria

Section: Chapter Questions

Problem 77QAP

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(CH3)2O →BF3(g)⇋BF3(g)+(CH3)2O(g) If you place 1.2 g of the complex in a 61.5 mL flask at 125 ℃, what is the total pressure in the flask at equilibrium? What are the partial pressures of the Lewis Acid, Lewis Base, and the complex? (Given: The value of K (here Kp) for the reaction is 0.17 at 125 ℃.) P(BF3)= P((CH3)2O)= P((CH3)2O→BF3)=

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