Answered: EF, = 0 Pac cos 60° – PaB cos 40° = 0… | bartleby

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How do you get those values of P_AB and P_AC

Fx = 0 I PAC cos 60° – PAB cos 40° = 0
EF, = 0 +1 PAC sin 60° + PAB sin 40° – W = 0
Solving simultaneously, we get
PAB = 0.5077W
Рс — 0.7779 W

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