Ed's Tires and Brakes has two locations, one on the northwest side of town and one on the southeast side of town. At both locations are performed routine tire repairs and rotations, as well as expensive brake repairs. This past week, 75% of the cars serviced at Ed's were serviced at the northwest location, while 25% of the cars were serviced at the southeast location. (No car was serviced at both locations.) Brake repairs were more typical at the northwest location than at the southeast location: 60% of the cars at the northwest location required brake repairs, while 40% of the cars at the southeast location required brake repairs. Let N denote the event that a randomly chosen car (taken to Ed's in the past week) was serviced at the northwest location and N denote the event that a randomly chosen car was serviced at the southeast location. Let B denote the event that a randomly chosen car required brake repairs and B denote the event that a randomly chosen car did not require brake repairs. Fill in the probabilities to complete the tree diagram below, and then answer the question that follows. Do not round any of your responses. (If necessary, consult a list of formulas.) P(B|N) = 0.6 P(N n B) = 0 %3D P (N) = 0.75 %3D P(N n 5) - O P(5|N) - P(3|N)= 04 P(Nn 3) =0 P(N P(Wn 5) = 0

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tiohal probabilities
Nejuanne v
Ed's Tires and Brakes has two locations, one on the northwest side of town and one on the southeast side of town. At both locations are performed routine tire
repairs and rotations, as well as expensive brake repairs. This past week, 75% of the cars serviced at Ed's were serviced at the northwest location, while 25% of
the cars were serviced at the southeast location. (No car was serviced at both locations.) Brake repairs were more typical at the northwest location than at the
southeast location: 60% of the cars at the northwest location required brake repairs, while 40% of the cars at the southeast location required brake repairs.
Let N denote the event that a randomly chosen car (taken to Ed's in the past week) was serviced at the northwest location and N denote the event that a
randomly chosen car was serviced at the southeast location. Let B denote the event that a randomly chosen car required brake repairs and B denote the event
that a randomly chosen car did not require brake repairs.
Fill in the probabilities to complete the tree diagram below, and then answer the question that follows. Do not round any of your responses.
(If necessary, consult a list of formulas.)
P(B|N) =
0.6
P (N n B) =
Aa
P (N) = 0.75
P (Nn 3) = |
%3D
PB
%3D
P(B
0.4
%3D
P(N n 3) = |
P(N) -0
P (N n E) = ]
%3D
Explanation
Check
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4)
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99+
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Transcribed Image Text:tiohal probabilities Nejuanne v Ed's Tires and Brakes has two locations, one on the northwest side of town and one on the southeast side of town. At both locations are performed routine tire repairs and rotations, as well as expensive brake repairs. This past week, 75% of the cars serviced at Ed's were serviced at the northwest location, while 25% of the cars were serviced at the southeast location. (No car was serviced at both locations.) Brake repairs were more typical at the northwest location than at the southeast location: 60% of the cars at the northwest location required brake repairs, while 40% of the cars at the southeast location required brake repairs. Let N denote the event that a randomly chosen car (taken to Ed's in the past week) was serviced at the northwest location and N denote the event that a randomly chosen car was serviced at the southeast location. Let B denote the event that a randomly chosen car required brake repairs and B denote the event that a randomly chosen car did not require brake repairs. Fill in the probabilities to complete the tree diagram below, and then answer the question that follows. Do not round any of your responses. (If necessary, consult a list of formulas.) P(B|N) = 0.6 P (N n B) = Aa P (N) = 0.75 P (Nn 3) = | %3D PB %3D P(B 0.4 %3D P(N n 3) = | P(N) -0 P (N n E) = ] %3D Explanation Check O 2021 McGraw-Hill Education. All Rights Reserved. Terms of Use Privacy Accessibility 12 4) 3/1 99+ O Type here to search
Tree diagrams for conditional probabilities
P (N n B) =
%3D
P(N) = 0.75
P(N n E) =
P(5N)-
%3D
P(8|x) -
0.4
P(N n 3) =0
P(N)
%3D
P (N n 5) =
P(5|N) =
What is the probability that a randomly chosen car required
brake repairs?
Explanation
Check
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O Type here to search
99+
#5602
Arus
stop Viris removal s A2 a
Transcribed Image Text:Tree diagrams for conditional probabilities P (N n B) = %3D P(N) = 0.75 P(N n E) = P(5N)- %3D P(8|x) - 0.4 P(N n 3) =0 P(N) %3D P (N n 5) = P(5|N) = What is the probability that a randomly chosen car required brake repairs? Explanation Check O 2021 McGraw-Hill Education, All Rights Reserved. Terms of Use I O Type here to search 99+ #5602 Arus stop Viris removal s A2 a
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