In a statistics activity, students are asked to spin a penny and a dime and determine the proportion of times thateach lands with tails up. The students believe that since a dime is lighter, it will have a lower proportion of timeslanding tails up compared with the penny. The students are instructed to spin the penny and the dime 30 times andrecord the number of times each lands tails up. For one student, the penny lands tails side up 18 times, and thedime lands tails side up 20 times. Let pp = the true proportion of times a dime will land tails up and pp = the trueproportion of times a penny will land tails up. The P-value for this significance test is 0.296. Which of the following isthe correct conclusion for this test of the hypotheses H Pp-Pp=0 and H, Po-Pp< o at the a =0.05 level?O The student should reject the null hypothesis since 0.296 > 0.05. There is sufficient evidence that the trueproportion of times a dime will land tails up is significantly less than the penny.O The student should reject the null hypothesis since 0.296 > 0.05. There is insufficient evidence that the trueproportion of times a dime will land tails up is significantly less than the penny.O The student should fail to reject the null hypothesis since 0.296 > 0.05. There is sufficient evidence that the trueproportion of times a dime will land tails up is significantly less than the penny.O The student should fail to reject the null hypothesis since 0.296 > 0.05. There is insufficient evidence that the trueproportion of times a dime will land tails up is significantly less than the penny.Mark this and returnSave and ExitSubmit79.

The p-value is given by 0.296 And the level of significance = 0.05

Answered: the correct conclusion for this test of…

Math

Statistics

the correct conclusion for this test of the hypotheses H Pp-Pp=0 and H Po-Pp< 0 at the a =0.05 level?

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: In a previous year, 56% of females aged 15 years of age and older lived alone. A sociologist tests…

A: From the provided information, Sample size (n) = 700 From which 406 are living alone. Level of…

Q: Last part is: What is the appropriate conclusion for this test? (Do not reject OR reject) H₀ and…

A: The objective of this question is to test the hypothesis that mice with an average life span of 32…

Q: (Problem for Questions 22- 25). In a study focusing on children on the autism spectrum a team of…

A: The Chi-square test statistic is χ2=∑i=1n(fi-ei)2eiwhere,fi=observed frequencyei=expected…

Q: A researcher conducts a hypothesis test using a sample of n=20 with M =34 and s^2=36 from an unknown…

A: Here, the known values are n=20 with M =34 and s2=36.

Q: A hypothesis test is conducted with H0 : µ1 - µ2 = -5 vs. Ha: µ1 - µ2 < -5 . Which of the following…

A: Given Information: H0:μ1-μ2=-5 vs Ha:μ1-μ2<-5n1=15x1¯=51.5s1=2.5n2=8x2¯=59.3s2=1.9

Q: In a previous year, 56% of females aged 15 and older lived alone. A sociologist tests whether this…

A: We have given that p0 = 56% = 0.56n = 500x = 274p̂ = x/n = 274/500 = 0.548Significance level (α) =…

Q: Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone…

A: It is given that our environment is very sensitive to the amount of ozone in the upper atmosphere.…

Q: Suppose 249249 subjects are treated with a drug that is used to treat pain and 5050 of them…

A: Null hypothesis: Alternative hypothesis:

Q: Step 1 From the provided information, Sample size (n) = 30 Sample mean (x) = 111 Sample standard…

A: Given: Test Statistics = -28.9971 degree of freedom =29 Obtained p value = 0.00001

Q: Use the given information to find the P-value. Also, use a 0.05 significance level and state the…

A: Note : Accord8ng to our guidelines we are solving only first question i.e Question 4 and rest…

Q: The concentration of a particular chemical in a processing plant is monitored regularly to check…

A: To carry out the statistical test, we can use a one-sample t-test to determine if the mean…

Q: uestion Completion Status: Complete the following ANOVA table for a study with k = 3 and N = 98. The…

Q: You are performing a two-tailed test with test statistic z=0.21z=0.21, find the p-value to 4 decimal…

A: The type of test is two tailed test. The value of test statistic is, z = 0.21

Q: QUESTION 39 You compute the probability of type Il error to be 0.6, what is power (value of that…

A: From the given information we find the solution.

Q: A simple random sample of size nequals=40 is drawn from a population. The sample mean is found to be…

A: It is given that:

Q: sample of 30 college students had left an average tip of $3.31, with a standard deviation of andom…

Q: You are performing a left-tailed t - test with test statistic t= −0.56 and a sample of size 15, find…

A: Given that the sample size= 15 So the degrees of freedom= DF= 15-1=14 Test statistic= t= −0.56

Q: 1. Consider a population with proportion p. Let X be the number of successes in a random sample of…

A: 1. The is a random variable representing the number of successes in a random sample size such…

Q: te the value used in obtaining the overall Chi-squared statistic for the cell “Low Dose- Lived “…

A: Given, Observed frequency (O) Table: By applying the chi-square of independence,

Q: Please solve this by hand and also with r-studio code not the excel output please. An experimenter…

A: The given hypothesis is H0:μ=420 versus Ha:μ<420.

Q: What is the value of the test statistic for a test with a null hypothesis that mu = 98.6, Xbar =…

A: Answer The population mean [mu] = 98.6,Xbar = 100.4,the standard error [SE] = 4, and n = 16

Q: A researcher was doing a study for a new Coronavirus Drug and conducted a hypothesis test like this…

A: a, Since the alternative hypothesis is μ = 15 , so this is a two tailed test. Hence 2nd option is…

Q: You are performing a two-tailed t-test with test statistic t=2.42 and a sample of size 45, find the…

A: Given that, n = 45 The type of test is two tailed test The value of test statistic is, t = 2.42 The…

Q: The proportion of on-line shoppers who actually make a purchase appears to be relatively constant…

A: The random variable purchased merchandise follows binomial distribution. There are two samples which…

Q: You are performing a two-tailed test with test statistic z=1.99z=1.99, find the p-value to 4 decimal…

Q: You are performing a two-tailed t- test with test statistic t = 1.92 and a sample of size 14, find…

A: Given data: Two tailed test t = 1.92 Sample size (n) = 14

Q: You are performing a right-tailed test with test statistic z=1z=1, find the p-value to 4 decimal…

A: When performing a right tailed test, the p-value is given by PH0[Z>z], where Z is the test…

Q: 12. A hypothesis test is conducted with H0 : µd = -1 vs. Ha : µd < -1 . Which of the following…

A: Given data: The given hypothesis test is left tailed test.Also here population standard deviation is…

Q: • Find the p-value for a two-tailed test of hypothesis for a mean when the test statistic has been…

Q: Why is the null hypothesis for a dependent-samples t- test always μD=0 μD=0 ?

A: Hypothesis is a statement or claim above property of population. Null Hypothesis: states that there…

Q: Step 3: Find the p-value of the point estimate. First identify the observed and expected values.…

A: Given: As we have to test that if coin is fair, so each outcome should be equally likely with…

Q: A hypothesis test of the null hypothesis μ-135 yields a z-test statistic of 1.05. What is the…

Q: A sample of size 81 is taken from a population with unknown mean and standard deviation 4.5. In a…

A: Solution-:Given: We want to find which of the following is true.(i) We would fail to reject the null…

Q: You are performing a right-tailed t test with test statistic t = 2.04 and a sample of size 27, find…

Q: Zobt of 3.33 falls in the Critical Region (Rejection Region) with Zerit of| Therefore, the result…

A: The observed test statistic is,

Q: Given the null and alternative hypotheses, sample means, sample sizes, and population standard…

A: To check the mean difference between two groups, when the population standard deviations are known…

Q: K Find the critical values X1-a/2 and Xa/2 for a 80% confidence level and a sample size of n = 25.…

A: Sample size n=25

Q: The display provided from technology available below results from using data for a smartphone…

A: Suppose, X be the smartphone carrier's data speeds at airports. X follows normal distribution with…

Q: test statistic for a hypothesis test on a proportion came out to z=−1.82z=-1.82 ALSO illustrate the…

A: The z score distribution is also known as a standard normal distribution. In the standardized form,…

Concept explainers

Confidence Intervals

When we calculate intervals in probability and statistics, it can be simply termed as finding out a confidence interval. The confidence interval is usually calculated from the data set which is observed. The value of the parameter that needs to be calculated is present here only.

Question

100%

In a statistics activity, students are asked to spin a penny and a dime and determine the proportion of times that
each lands with tails up. The students believe that since a dime is lighter, it will have a lower proportion of times
landing tails up compared with the penny. The students are instructed to spin the penny and the dime 30 times and
record the number of times each lands tails up. For one student, the penny lands tails side up 18 times, and the
dime lands tails side up 20 times. Let pp = the true proportion of times a dime will land tails up and pp = the true
proportion of times a penny will land tails up. The P-value for this significance test is 0.296. Which of the following is
the correct conclusion for this test of the hypotheses H Pp-Pp=0 and H, Po-Pp< o at the a =0.05 level?
O The student should reject the null hypothesis since 0.296 > 0.05. There is sufficient evidence that the true
proportion of times a dime will land tails up is significantly less than the penny.
O The student should reject the null hypothesis since 0.296 > 0.05. There is insufficient evidence that the true
proportion of times a dime will land tails up is significantly less than the penny.
O The student should fail to reject the null hypothesis since 0.296 > 0.05. There is sufficient evidence that the true
proportion of times a dime will land tails up is significantly less than the penny.
O The student should fail to reject the null hypothesis since 0.296 > 0.05. There is insufficient evidence that the true
proportion of times a dime will land tails up is significantly less than the penny.
Mark this and return
Save and Exit
Submit
7
9.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Basics of Inferential Statistics$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

Number 4
A researcher is to perform a hypothesis test for a single population mean with null and alternative hypotheses given below. HoiH=2500 Hail> 2500 The researcher collects a sample of size Calculate the p-value. n= 57 with sample mean y=2513 and sample standard deviation s= 121.3: Answer as a decimal and not a percentage with accuracy to at least 2 decimal places.
Assume that MLR1-6 hold. We can say that the coefficient is statistically significant at the 5% level if the t-statistic is less than -2 and the degrees of freedom are larger than 60. True False
In order to conduct a hypothesis test of the population mean, Prof. Leen draws a random sample of 35 observations from a normally distributed population with population standard deviation 1.8. The mean for the sample is 12.8. The hypotheses are H0: μ ≤ 12.5, HA: μ > 12.5 (a) Calculate the value of the test statistic. (Round your answer to 2 decimal places.) (b) Give the p-value. (Round to three decimal places.)
42
Is this correct
None
21
We collected a sample of twenty-five observations. We assumed that the observations are from a population whose values follow a normal distribution with a mean of u and a standard deviation of five. We performed a test with these hypotheses Ho: OHμ = 0 and H₂₁:μ‡0H₁0. The test statistic is the sample mean . The 5% rejection region is 1.959964> 1.959964. What is the power of this test when μ = -2 = -2? Please state the statistical power up to the fourth decimal place.
A previous study showed to determine whether a sales tax on soda will reduce consumption of soda in the US below the current per-capita level of about 50 gallons of soda per year. Hypotheses Test is Ho: m(mue) =50 vs. Ha: m<50 where m (mue) represents the average annual consumption of soda in communities where the sales tax is implemented. (a) Supposed sample results give a p-value of 0.02. Interpret this p-value in terms of random chance and in the context of taxes and soda consumption.
Regarding question 8.) Please let me know why critical point at 95% confidence of t-statistic of df (n1+n2-2) = 32 is 2.034, not +/- 2.73 which is from T-value table.
The life expectancy of a male during the course of the past 100 years is approximately 27,715 days. Use the table to the right to conduct a test using a=0.05 to determine whether the evidence suggests that chief justices live longer than the general population of males. Suggest a reason why the conclusion drawn may be flawed. State the appropriate null and alternative hypotheses. O A. Ho: p=27,715 versus H₁: μ27,715 O E. Ho: p=30,747 versus H,: μ#30,747 Chief Life Chief Justice Span (Days) Justice A I J K L M N 0 P BCDEFGH 31,073 29,372 Ioanngildin 30,227 28,918 32,452 32,628 26,577 32,592 Life Span (Days) 32,934 27,432 HERITATION 30,629 OB. Ho: H=27,715 versus H₁: p #27,715 OD. Ho H=30,747 versus H₁: 30,747 1967 30,930 32.407 28,319 32,741 32,716 ted ny