proof the equation 10.8 which represents the gain of inversting amplifer ... the proof is already exist in page 621 but there are some expressions were missed before the equation 10.7, you should start this proof from the begining and adding that missed expressions. each of the sources. PUVR+ RFor source -A, V, only (V set to zero),RL(-A,V)R+ RThe total voltage V; is thenV; = V + VigR1-V+(-A,V)%3DR + R;R + Rjwhich can be solved for V, as(10.7)-V1Rf + (1 + A,)R1V, =If A, >1 and A, R > R as is usually true, thenRfV =A,R1Solving for V/V, we getVRy Vi-A, RV1V A,R1-A,Vi%3D%3DR1 Vịso thatVoRf(10.8)VIR1

In the case of Inverting amplifier, the input signal is given to the Negative pin of an operational…

Answered: each of Rf V1 R+R For source -A, V,…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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proof the equation 10.8 which represents the gain of inversting amplifer ... the proof is already exist in page 621 but there are some expressions were missed before the equation 10.7, you should start this proof from the begining and adding that missed expressions.

each of the sources. PU
V
R+ R
For source -A, V, only (V set to zero),
RL
(-A,V)
R+ R
The total voltage V; is then
V; = V + Vig
R1
-V+
(-A,V)
%3D
R + R;
R + Rj
which can be solved for V, as
(10.7)
-V1
Rf + (1 + A,)R1
V, =
If A, >1 and A, R > R as is usually true, then
Rf
V =
A,R1
Solving for V/V, we get
V
Ry Vi
-A, RV1
V A,R1
-A,Vi
%3D
%3D
R1 Vị
so that
Vo
Rf
(10.8)
VI
R1

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