Each Carbon in benzene is sp2 hybradized. What is not true for sp2 hybridization? Question 6 options: One of the p orbitals of Carbon remains unhybradized which is utilized to form a pi bond sp2 hybrid orbital of one carbon atom overlaps with sp2 hybrid orbital of adjacent Carbon atom to give a Pi bond sp2 hybrid orbitals have 1:2 ratio of s and p One s and two p orbitals of Carbon combine to give three equivalent sp2 hybrid orbitals The sp2 hybrid orbitals are planar and arranged at an angle of 120o

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Answered: Each Carbon in benzene is sp2…

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Each Carbon in benzene is sp²hybradized. What is not true for sp²hybridization?

Question 6 options:

	One of the p orbitals of Carbon remains unhybradized which is utilized to form a pi bond
	sp² hybrid orbital of one carbon atom overlaps with sp² hybrid orbital of adjacent Carbon atom to give a Pi bond
	sp² hybrid orbitals have 1:2 ratio of s and p
	One s and two p orbitals of Carbon combine to give three equivalent sp²hybrid orbitals
	The sp²hybrid orbitals are planar and arranged at an angle of 120^o