### Question 5When 3.66 g of CaO (molar mass: 56.08 g/mol) is added to 50.0 g of water at 25.0 °C in a calorimeter, the temperature of the water increases to 32.3 °C. Assuming the specific heat of the solution is 4.184 J/g°C and that the calorimeter itself absorbs no heat, calculate ΔH in kJ/mol for the reaction below. Enter the answer to 3 significant figures.\[ \text{CaO(s) + H}_2\text{O(l) → Ca(OH)}_2\text{(aq)} \]#### Explanation:This is a calorimetry problem that requires calculating the heat change (ΔH) for the reaction given the specific conditions. It involves determining the amount of heat absorbed by the solution and then converting that into ΔH for the reaction on a molar basis. 1. Calculate the heat absorbed by the water using \( q = mc\Delta T \). - \( m \) = mass of the water solution (including CaO), - \( c \) = specific heat, - \( \Delta T \) = change in temperature.2. Convert the heat absorbed into kJ/mol, using the given molar mass of CaO.This involves both theoretical understanding and mathematical calculation steps.

The heat absorbed (q) by water is calculated using the formula- q=m×C×∆T where m is the mass of…

Ea CaO(s)+H₂O(1)→ Ca(OH)2 QUESTION 5 When 3.66 g of CaO (molar mass: 56.08 g/mol) is added to 50.0g of w specific heat of the solution is 4.184 J/g-°C and that the calorimeter itself absorb significant figures npf a photon (select all that apply)?

Ea CaO(s)+H₂O(1)→ Ca(OH)2 QUESTION 5 When 3.66 g of CaO (molar mass: 56.08 g/mol) is added to 50.0g of w specific heat of the solution is 4.184 J/g-°C and that the calorimeter itself absorb significant figures npf a photon (select all that apply)?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Part A Open the activity depicting Hess's Law. N:(g) + 0:(g) → 2NOg AH is an Extensive Property N: ( +0:(g) → NO(g) AH is an Extensive Property Click the button within the activity, and analyze the relationship between the two reactions that are displayed. The reaction that was on the screen when you started and its derivative demonstrate that the change in enthalpy for a reaction, AH, is an extensive property. Using this property, calculate the change in enthalpy for Reaction 2. AH Canges sign when a process is revTsed 2NO2) > N:(g) + 0: (g Reaction 1: C3 Hs(g)+ 502 (g)→3CO2 (g) + 4H2O(g), AH1 = -2043 kJ Hess's Law of Constant Heat Sumnation + N: (g) +0: (g) → deg Reaction 2: 5C3 Hs(g) +25O2(g)→15CO2(g) +20H,O(g), AH2 =? When two reactions are added together. the individual reaction enthalpies are summed. Notice that equal quantities of the same species, on both sides of the reaction arrow, cancel. NQg) +0: g) → NO: (g) Express your answer to four significant figures and include the…
A container filled with 3.29 kg of water underwent a temperature change from 23.89 °C to 28.28 °C. How much heat, measured in kilojoules, did the water absorb? (The specific heat of water is 4.18-J.g1,ºC-1). kJ e Textbook and Media Hint Save for Later Attempts: 0 of 2 used Submit Answer. "pe'here to search a 成中 o 4+ ha insert prt 144 & 24 4 @ %23 8. E bac 3 Q W E T Y U F G H KL A S pause X. C V B|| N M alt ctri alt R
Using Hess's law find the final enthalpy which is delta H! Show your steps! We know delta H is -283.46kJ/mol for this reaction, however how did we get that!
I Review | Constants | Periodic Table Open the activity depicting Hess's Law. N:(g) + 0: (g) → 2NOg) Part A AH is an Extensive Property + N: (g) + O:(g) → NO(g) AH is an Extensive Property Click the the screen when you started and its derivative demonstrate that the change in enthalpy for a reaction, AH, is an extensive property. Using this property, calculate the change in enthalpy for Reaction 2. AH Changes sign when a process is nevTNed 2NO2) N:(g) + 0:(g) button within the activity, and analyze the relationship between the two reactions that are displayed. The reaction that was on Hesss Law of Constant Heat Sunnaticn + N: (g) +0: (g) → dog Reaction 1: C3 Hs(g) + 502(g)→3CO2(g) + 4H20(g), AH1 = -2043 kJ When two reactions are added together, the individual reaction enthalpies are summed. Notice that equal quantities of the same species, on both sides of the reaction arnow, cancel. NQig) + +0: → NO: (2) Reaction 2: 5C3 Hs(g) + 2502(g)→15CO2 (g) + 20H2O(g), AH2 =? - N: (g) + O: (g) →…
Consider these reactions: Reaction 1: H₂(g) + Cl₂(g) Reaction 2: Reaction 3: - 20F 2(g) ->> O2(g) + 2 F2 (g) AH = -49.4 kJ 2HCl(g) AH = -184.6 kJ N₂(g) +202 (8) -> Use Reaction 2. Answer: How much energy (in kJ) is released when 71.0 g of oxygen difluoride decomposes? Enter a positive number. Round to the nearest hundredth. 2NO2(g) AH = +66.4 kJ KJ
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