In these experiment, you will be analyzing the parallel plate capacitor which is represented below. Thearea of the capacitor and the separation between the plates are adjustable. The capacitance of the setupcan be calculated from: C = Kair€oh × L/d. In the setup, you will analyze dependance of C on Area, andon d. Area will be adjusted by changing the length L.HINT: Recall that K = 1.00059 ~ 1, and ɛo = 8.85 x 10-12 F/m (C²/Nm2).|CAUTION:You will be reading the capacitance value by using a multimeter.• Arrange the scale of the multimeter to the smallest possible scale.• Before each reading, always discharge the capacitor by connecting the plates with awire. E2.3 What should be the area of the parallel plates to measure a capacitance of 1 F, if the separation|between the plates is 1 mm. Estimate roughly.Area =.m².

Given data: Capacitance (C) = 1 F Separation between the plates (d) = 1 mm = 1 × 10-3 m ε0 = 8.85 ×…

Answered: E2.3 What should be the area of the…

E2.3 What should be the area of the parallel plates to measure a capacitance of 1 F, if the separation between the plates is 1 mm. Estimate roughly. Area ..m?.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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