e the superposition principle to find to in the circuit below: 12 R₁ www R₂ www V3 Ro Given that: I₁=4 A and I₂ = 8 A • V₂ = 13 V • R₁ = 139, R₂ =9ft, and Re = 6 ft Find the voltage Answer: Given that I₁=4 A and I₂ = 8 A by the current source I₁. • V₂ = 13 V R₁ = 13 ft. R₂ =9ft, and Re=6f Find the voltage Answer: Answer: by the current source 1₂. Given that: • I₁=4 A and I₂ = 8 A • V₂ = 13 V • R₁ = 13 ft. R₂ =9f, and Ro=6ft Find the voltage ty by the voltage source V₂.

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### Superposition Principle Example in Circuit Analysis

In this educational exercise, we will apply the superposition principle to a given circuit to find the voltage \(v_0\). The circuit diagram and given values are displayed below.

#### Circuit Diagram

[Diagram of the circuit]

**Components:**
- \(I_1\): Current source
- \(I_2\): Current source
- \(V_3\): Voltage source
- \(R_1\): Resistor 
- \(R_2\): Resistor
- \(R_0\): Resistor
- \(v_0\): Output voltage across resistor \(R_0\)

**Given Values:**
- \( I_1 = 4 \, \text{A} \)
- \( I_2 = 8 \, \text{A} \)
- \( V_3 = 13 \, \text{V} \)
- \( R_1 = 13 \, \Omega \)
- \( R_2 = 9 \, \Omega \)
- \( R_0 = 6 \, \Omega \)

We will determine the output voltage \( v_0 \) as follows:

### Step 1: Find \(v_{1}\) By Considering Only \(I_{1}\)
To isolate \( I_1 \), deactivate \( I_2 \) by replacing it with an open circuit and deactivate \( V_3 \) by replacing it with a short circuit.

**Find the voltage \( v_{1} \) by the current source \( I_{1} \).**

\[ \text{Answer:} \, \_\_\_\_\_\_ \]

### Step 2: Find \(v_{2}\) By Considering Only \(I_{2}\)
To isolate \( I_2 \), deactivate \( I_1 \) by replacing it with an open circuit and deactivate \( V_3 \) by replacing it with a short circuit.

**Find the voltage \( v_{2} \) by the current source \( I_{2} \).**

\[ \text{Answer:} \, \_\_\_\_\_\_ \]

### Step 3: Find \(v_{3}\) By Considering Only \(V_{3}\)
To isolate \( V_3 \), deactivate \( I_1 \) and \( I_2 \) by replacing both with open circuits.

**
Transcribed Image Text:### Superposition Principle Example in Circuit Analysis In this educational exercise, we will apply the superposition principle to a given circuit to find the voltage \(v_0\). The circuit diagram and given values are displayed below. #### Circuit Diagram [Diagram of the circuit] **Components:** - \(I_1\): Current source - \(I_2\): Current source - \(V_3\): Voltage source - \(R_1\): Resistor - \(R_2\): Resistor - \(R_0\): Resistor - \(v_0\): Output voltage across resistor \(R_0\) **Given Values:** - \( I_1 = 4 \, \text{A} \) - \( I_2 = 8 \, \text{A} \) - \( V_3 = 13 \, \text{V} \) - \( R_1 = 13 \, \Omega \) - \( R_2 = 9 \, \Omega \) - \( R_0 = 6 \, \Omega \) We will determine the output voltage \( v_0 \) as follows: ### Step 1: Find \(v_{1}\) By Considering Only \(I_{1}\) To isolate \( I_1 \), deactivate \( I_2 \) by replacing it with an open circuit and deactivate \( V_3 \) by replacing it with a short circuit. **Find the voltage \( v_{1} \) by the current source \( I_{1} \).** \[ \text{Answer:} \, \_\_\_\_\_\_ \] ### Step 2: Find \(v_{2}\) By Considering Only \(I_{2}\) To isolate \( I_2 \), deactivate \( I_1 \) by replacing it with an open circuit and deactivate \( V_3 \) by replacing it with a short circuit. **Find the voltage \( v_{2} \) by the current source \( I_{2} \).** \[ \text{Answer:} \, \_\_\_\_\_\_ \] ### Step 3: Find \(v_{3}\) By Considering Only \(V_{3}\) To isolate \( V_3 \), deactivate \( I_1 \) and \( I_2 \) by replacing both with open circuits. **
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