e temperature of an object increases by 43.3 °C when it absorbs 3851 J of heat. Calculate the heat capacity of the object. = e mass of the object is 371 g. Use the table of specific heat values to identify the composition of the object. Substance gold Specific heat (J/(g · °C)) . 0.129 silver 0.240 iron 0.444 aluminum 0.900 The object is composed of 000 О gold. aluminum. silver. iron. J/°

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The temperature of an object increases by 43.3 °C when it absorbs 3851 J of heat. Calculate the heat capacity of the object.
C =
The mass of the object is 371 g. Use the table of specific heat values to identify the composition of the object.
Substance
gold
Specific heat (J/ (g ⋅ °C))
0.129
silver
0.240
iron
0.444
aluminum
0.900
The object is composed of
gold.
aluminum.
silver.
○ iron.
J/°C
Transcribed Image Text:The temperature of an object increases by 43.3 °C when it absorbs 3851 J of heat. Calculate the heat capacity of the object. C = The mass of the object is 371 g. Use the table of specific heat values to identify the composition of the object. Substance gold Specific heat (J/ (g ⋅ °C)) 0.129 silver 0.240 iron 0.444 aluminum 0.900 The object is composed of gold. aluminum. silver. ○ iron. J/°C
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