e sure to answer all parts. The reaction of peroxydisulfate ion (S₂0²) with iodide ion (I) is 208² (aq) + 31 (aq) → 2SO4 (aq) + 13 (aq) From this data collected at a certain temperature, calculate the rate constant. k = Exp. 1 2 3 Ms [S₂02] [r] (M) (M) 0.0800 0.0800 Initial Rate (M/s) 0.0340 4.50 x 10-4 0.0170 2.25 x 10-4 0.0170 4.50 x 10-4 0.160
e sure to answer all parts. The reaction of peroxydisulfate ion (S₂0²) with iodide ion (I) is 208² (aq) + 31 (aq) → 2SO4 (aq) + 13 (aq) From this data collected at a certain temperature, calculate the rate constant. k = Exp. 1 2 3 Ms [S₂02] [r] (M) (M) 0.0800 0.0800 Initial Rate (M/s) 0.0340 4.50 x 10-4 0.0170 2.25 x 10-4 0.0170 4.50 x 10-4 0.160
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Be sure to answer all parts.
The reaction of peroxydisulfate ion (S₂0g2) with iodide ion (I) is
S₂O² (aq) + 31 (aq) → 2SO4 (aq) + 13(aq)
From this data collected at a certain temperature, calculate the rate constant.
k =
Exp.
1
2
3
Ms
[S₂08] [r]
(M)
(M)
0.0800
0.0800
Initial
Rate
(M/s)
0.0340 4.50 x 10-4
0.0170 2.25 x 10-4
0.0170 4.50 x 10-4
0.160](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F416d7951-182a-468a-b164-e1b2047c3e85%2Faba5d52e-0b9f-4dd7-a40e-a2c4abb753cf%2Flfo91vj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Be sure to answer all parts.
The reaction of peroxydisulfate ion (S₂0g2) with iodide ion (I) is
S₂O² (aq) + 31 (aq) → 2SO4 (aq) + 13(aq)
From this data collected at a certain temperature, calculate the rate constant.
k =
Exp.
1
2
3
Ms
[S₂08] [r]
(M)
(M)
0.0800
0.0800
Initial
Rate
(M/s)
0.0340 4.50 x 10-4
0.0170 2.25 x 10-4
0.0170 4.50 x 10-4
0.160
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