2A(g) + 3/2B(g) Experiment 1 a) b) c) d) k= 2345 ->> C(g) Initial rate (mol/L.s) (mol/L) 0.25*10-4 2.25x10-4 0.50*10-4 1.00×10-4 0.75*10-4 Initial [A] 5x10-2 15x10-2 5*10-2 10×10-2 5x10-2 unit: Rate = K[A][B]¹ Overall reaction order is Initial [B] (mol/L) 5x10-2 5x10-2 Reaction order with respect to A is 10×10-2 5x10-2 15x10-2 Reaction order with respect to B is ( Calculate rate constant (k) based on data from experiment 3:

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter7: Reaction Rates And Chemical Equilibrium
Section: Chapter Questions
Problem 7.67P
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Question
2A(g) + 3/2B(g)
Experiment
e
b)
D
d)
k=
12345
Initial rate
(mol/L.s)
→→ C(g)
0.25*10-4
2.25x10-4
0.50×10-4
1.00×10-4
0.75*10-4
Initial [A]
(mol/L)
5x10-2
15x10-2
5x10-2
10×10-2
5x10-2
unit:
Overall reaction order is
Rate = K[A][B]
Initial [B]
(mol/L)
Reaction order with respect to A is
Reaction order with respect to B is
5x10-2
5x10-2
10x10-2
5x10-2
15x10-2
O
"
O
Calculate rate constant (k) based on data from experiment 3:
Transcribed Image Text:2A(g) + 3/2B(g) Experiment e b) D d) k= 12345 Initial rate (mol/L.s) →→ C(g) 0.25*10-4 2.25x10-4 0.50×10-4 1.00×10-4 0.75*10-4 Initial [A] (mol/L) 5x10-2 15x10-2 5x10-2 10×10-2 5x10-2 unit: Overall reaction order is Rate = K[A][B] Initial [B] (mol/L) Reaction order with respect to A is Reaction order with respect to B is 5x10-2 5x10-2 10x10-2 5x10-2 15x10-2 O " O Calculate rate constant (k) based on data from experiment 3:
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