Table 2: Q vs. KeKeDirection the Reaction Proceeds to Attain EquilibriumRelationshipQ.(s, =, >) K.Exp.(forward toward products OR reverse toward reactants)14 Wilbur Wright CollegeREPORTTable 1: Initial & Equilibrium Concentrations[Fe") (M)[SCN] (M)(FESCN) (M)(Fe"l (M)5.58 10 M(SCN J (M)(FESCN (M)4.42 *10 MExp.5.58 *10 M10.0100.0103.38 *10 M3.38 * 10 M1.62 10 M20.00500.00504.55 10 M4.55 10 M2.95 10 M30.00500.00500.00254.99* 10 M8.49 10 M6.01 10 M40.00250.00600.00852.9* 20 M1.41 10 M5.85 10 M50.00300.00150.000560.00300.00570.00895.50* 10 M8.20* 10 M6.40* 10 M9.22* 10 M6.32* 10 M8.28* 10 M0.00860.00570.0089

Answered: Table 2: Q vs. K Relationship Q(S,,>) K…

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Table 2: Q vs. Ke
Ke
Direction the Reaction Proceeds to Attain Equilibrium
Relationship
Q.(s, =, >) K.
Exp.
(forward toward products OR reverse toward reactants)
1
4

Wilbur Wright College
REPORT
Table 1: Initial & Equilibrium Concentrations
[Fe") (M)
[SCN] (M)
(FESCN) (M)
(Fe"l (M)
5.58 10 M
(SCN J (M)
(FESCN (M)
4.42 *10 M
Exp.
5.58 *10 M
1
0.010
0.010
3.38 *10 M
3.38 * 10 M
1.62 10 M
2
0.0050
0.0050
4.55 10 M
4.55 10 M
2.95 10 M
3
0.0050
0.0050
0.0025
4.99* 10 M
8.49 10 M
6.01 10 M
4
0.0025
0.0060
0.0085
2.9* 20 M
1.41 10 M
5.85 10 M
5
0.0030
0.0015
0.0005
6
0.0030
0.0057
0.0089
5.50* 10 M
8.20* 10 M
6.40* 10 M
9.22* 10 M
6.32* 10 M
8.28* 10 M
0.0086
0.0057
0.0089

Expert Solution

Relation between reaction quotient and equilibrium constant

Since you have posted multiple sub-parts, we will solve the first three sub-parts. If you want the other parts to be solved, please post the questions with the specific sub-parts.

The given reaction is:

${Fe}^{+ 3} + {SCN}^{-} ⇌ {[Fe (SCN)]}^{2 +} Q_{c} = \frac{[Fe {(SCN)}^{2 +}]}{[{Fe}^{+ 3}] [{SCN}^{-}]} . . . (1) K_{c} = \frac{[Fe {(SCN)}^{2 +}]}{[{Fe}^{+ 3}] [{SCN}^{-}]} . . . (2)$

The reaction quotient, Q_c is written in the same way as that of the equilibrium constant. However, in Q_c, the reaction may or may not be in equilibrium. Three cases arise:

If Q_c = K_c, then the reaction is at equilibrium.
If Q_c> K_c, then the reaction will proceed in backward direction.
If Q_c< K_c, then the reaction will proceed in forward direction.

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