SUPOThe proportion p of residents in a community who recycle has traditionally been 70%. A policy maker claims that the proportion is less than 70% now that oneof the recycling centers has been relocated. If 138 out of a random sample of 220 residents in the community said they recycle, is there enough evidence tosupport the policy maker's claim at the 0.10 level of significance?Perform a one-tailed test. Then complete the parts below.Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.)(a) state the null hypothesis Ho and the alternative hypothesis H₁.Ho : 0H₁(b) Determine the type of test statistic to use.(Choose one) ▼(c) Find the value of the test statistic. (Round to three or more decimal places.)0(d) Find the p-value. (Round to three or more decimal places.)7(e) Is there enough evidence to support the policy maker's claim that theproportion of residents who recycle is less than 70%?XYes NoWUXㅁ0=0*XOSO5р

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Answered: e proportion p of residents in a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Q8. Please help.
Which of these scenarios means that a pretest-posttest design with a non-equivalent control group is not suitable? Select all that apply. O a. All of the available participants will be receiving the intervention at the same time. O b. Authors want to examine for any trends in the data over time. O c. The participants were placed into the experimental and control groups by natural circumstances rather than random assignment. O d. Authors want to compare averages between two groups before and after the intervention using an ANOVA.
Claim: Most adults would erase all of their personal information online if they could. A software firm survey of 454 randomly selected adults showed that 56% of them would erase all of their personal information online if they could. Find the value of the test statistic.
Q7
The average house has 15 paintings on its walls. Is the mean larger for houses owned by teachers? The data show the results of a survey of 16 teachers who were asked how many paintings they have in their houses. Assume that the distribution of the population is normal. 18, 15, 17, 14, 16, 17, 18, 15, 15, 14, 14, 14, 15, 15, 16, 18 What can be concluded at the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: Select an answer v H1: Select an answer v c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the population mean is not significantly more than 15 at a = 0.05, so there is sufficient evidence to conclude that the population mean number of paintings that are in…
The work week for adults in the US that work full time is normally distributed with a mean of 47 hours. A newly hired engineer at a start-up company believes that employees at start-up companies work more on average then most working adults in the US. She asks 12 engineering friends at start-ups for the lengths in hours of their work week. Their responses are shown in the table below. Test the claim using a 10% level of significance. Hours 47 47 55 51 48 65 51 52 50 49 51 54 What are the correct hypotheses? Ho: Select an answer ✓ ? ✓ Ha: Select an answer ✓ Test Statistic= hours Based on the hypotheses, find the following: p-value= hours (Give answer to at least 4 decimal places.) (Give answer to at least 4 decimal places).
Q3.3 Normal, but why? A meal package for use at the space station is to be prepared by combining three separate components: protein, fruit/vegetable, and grains. Each of the components is to be randomly selected. Summary values for the caloric content for each of the components are given in the table. Component Protein (P) Fruit/vegetable (F) Grain (G) Mean (calories) 120 55 84 Stdv (calories) 6.4 Save Answer 1.0 3.6 Assume that the distributions of caloric content for each of the components are approximately normally distributed. Since the meal package consists of protein, fruit/vegetable, and grains, the total caloric content of a meal package is the random variable T, where T = P + F + G. Briefly explain why it is appropriate to say that T is approximately normally distributed. Q3.4 Probability Less than 275 Calories On your own piece of paper find the approximate probability that a randomly selected meal package will have less than 269 calories? (Draw an appropriate diagram, find a…
What is the comple solution and answer for this problem involving ANOVA?
Also need to find the standardized test statistic, decide whether to reject or fail to reject, and interpret the decision in the context of the claim.
Claim: Most adults would erase all of their personal information online if they could. A software firm survey of 455 randomly selected adults showed that 61% of them would erase all of their personal information online if they could. Find the value of the test statistic.
Several studies showed that after eating a low-fat cereal for two meals a day, subjects had lost some weight.A cereal companyfinanced this research. Identify what is wrong. Choose the correct answer below. A. Since the research is composed of voluntary response samples, there may be key data points missing. B. The data used in the studies is not reliable because it was not measured by the administrator. C. It is questionable that the sponsor is a cereal company because this sponsor can be greatly affected by the conclusion. D. It is not possible to take accurate measurements.
You are a researcher studying the antler size of male Alaskan Moose in a certain Alaska location. You gather a random sample of 18 male moose and record the width (in feet) of the antlers. The data is displayed in the table below. Estimate the mean antler width of all Alaskan male moose in this area. Use a 90% confidence level. 3.6 5.6 3.4 3.4 4 5.2 4.6 4.3 4.6 4.6 2.2 6.4 3.6 3.1 5.4 4.4 3.3 4.3 a) Find the confidence interval: < μμ < b) What is the margin of error of your interval? c) Interpret your 90% confidence interval in context.

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