E (eV) 0.00 -0.378 6. -0.544 2 -0.850 4 -1.512 -3.401 Balmer series Figure P28.19 ENERGY 2.

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The Balmer series for the hydrogen atom corresponds to electronic transitions that terminate in the state with quantum number n = 2 as shown in Figure P28.19. Consider the photon of longest wavelength corresponding to a transition shown in the figure. Determine (a) its energy and (b) its
wavelength. Consider the spectral line of shortest wavelength corresponding to a transition shown in the figure. Find (c) its photon energy and (d) its wavelength. (e) What is the shortest possible wavelength in the Balmer series?

E (eV)
0.00
-0.378
6.
-0.544 2
-0.850 4
-1.512
-3.401
Balmer
series
Figure P28.19
ENERGY
2.
Transcribed Image Text:E (eV) 0.00 -0.378 6. -0.544 2 -0.850 4 -1.512 -3.401 Balmer series Figure P28.19 ENERGY 2.
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