e E1 = 0.00 eV, E2 = 1.34 eV, and E3 = 3.95 eV. %3D %3D
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- 1Eg Q.1/ Prove that: ni = NcNy e Using Eg = Ec-Ev Solution: n.p = ni?Chapter 39, Problem 017 An electron in the n, state in the finite potential well of of Figure (a) absorbs 650 eV of energy from an external source. U U(x) Ug L. (a) Using the energy-level diagram of Figure (b), determine the electron's kinetic energy after this absorption, assuming that the electron moves to a position for which x > L.
- 1. Using the equation p-n+ N – N = 0 and assuming ND = Np and N4 = N4, calculate and plot (a) n versus T , (b) n versus 1/T, and (c) Ef-E¡ versus T for Si for 250 KConsider the energy levels of the Hydrogen atom. The allowed H-atom energy levels are given by the equation: En - 13.6 eV n² What is the energy gap between the two lowest energy levels in the Hydrogen atom? 10.2 eV 6.40 eV 12.1 eV 13.6 eV 3.40 eV