The concrete girders shown in the photo of the passenger car park-ing garage span 30 ft and are 15 ft on center. If the floor slab is 5 in.thick and made of reinforced stone concrete, and the specified liveload is 50 lb/ft? (see Table 1–4), determine the distributed load thefloor system transmits to each interior girder.TABLE 1-4 Minimum Live Loads*Live LoadLive LoadOccupancy or UsepsfkN/m?Occupancy or UsepsfkN/m?Assembly areas and theatersFixed seatsMovable seatsResidential602.87Dwellings (one- and two-family)Hotels and multifamily houses401.921004.79Garages (passenger cars only) 50Office buildingsLobbies2.40Private rooms and corridors401.92Public rooms and corridorsSchoolsClassroomsCorridors above first floor1004.791004.79Offices502.40401.92Storage warehouseLightНeavy803.831256.0011.97250*Reproduced with permission from Minimum Design Loads for Buildings and Other Structures, ASCE/SEI 7-10.

The dead load due to slab thickness will be: D=5"-(1/12)*150=62.5 lb/ft2 The live load=50 lb/ft2 The…

e concrete girders shown in the photo of the passenger car park- 3 garage span 30 ft and are 15 ft on center. If the floor slab is 5 in. ick and made of reinforced stone concrete, and the specified live ad is 50 lb/ft² (see Table 1–4), determine the distributed load the or system transmits to each interior girder. TABLE 1–4 Minimum Live Loads* Live Load Occupancy or Use psf kN/m? Occupancy or Use Residential Dwellings (one- and two-family) Hotels and multifamily houses Private rooms and corridors Public rooms and corridors Schools Assembly areas and theaters Fixed seats 60 2.87 Movable seats 100 4.79 Garages (passenger cars only) 50 Office buildings 2.40 Lobbies 100 4.79 Offices 50 2.40 Classrooms Storage warehouse Light Неavy Corridors above first floor 125 6.00 250 11.97

e concrete girders shown in the photo of the passenger car park- 3 garage span 30 ft and are 15 ft on center. If the floor slab is 5 in. ick and made of reinforced stone concrete, and the specified live ad is 50 lb/ft² (see Table 1–4), determine the distributed load the or system transmits to each interior girder. TABLE 1–4 Minimum Live Loads* Live Load Occupancy or Use psf kN/m? Occupancy or Use Residential Dwellings (one- and two-family) Hotels and multifamily houses Private rooms and corridors Public rooms and corridors Schools Assembly areas and theaters Fixed seats 60 2.87 Movable seats 100 4.79 Garages (passenger cars only) 50 Office buildings 2.40 Lobbies 100 4.79 Offices 50 2.40 Classrooms Storage warehouse Light Неavy Corridors above first floor 125 6.00 250 11.97

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: 3. Load Tracing Determine the Columns loads assuming: DL (decking, flooring, etc.) = 30 psf LL…

Q: QUESTION 13 What is the Total Safe Uniform Load (LL + DL) for an 18K6 Open Web Joist with a span…

Q: Q1: The cantilever reinforced concrete beam has a rectangular cross- section (b-250 mm) shown in the…

Q: Q#1 (a) Design the cross-section of the simply supported beam designed in class considering a limit…

A: Solution: Given: Span = 24 ft fc = 4 ksi fy = 60 ksi LL = 2 kip/ft DL = 1 kip/ft D= 20 in

Q: he load information for a floor type roof is given as follows. The design action (ULS) on the roof…

A: Following are the load combinations:1.5 DL + 1.5 LL1.12 DL + 1.12 LL + 1.12 WL0.9 DL + 1.5 WLHere,…

Q: The wood column has a thickness of 4 in. and a width of 6 in. Using the NFPA equations of Sec. 13.6…

A: Given Data. The thickness of the wood column is t=4 in. The width of the wood column is b=6 in. The…

Q: Complete Loading calculation (floors and roof dead load calculations including estimated loads of…

A: where, A=40 ftB=19 ftC=9ftThe given building is a school located in Los Angeles, CATo determine:Dead…

Q: 2) A short braced reinforced concrete column supports an approximately symmetrical arrangement of…

A: Total vertical load(P)=1750 kN Area of steel(Asc)=1.5% of gross area(Ag) The concrete grade is 40…

Q: Calculate the factored moment strength of the slab below. If the only dead load the slab has to…

Q: (a) The detached servant room of a quarter is having internal size of 3.0mxx4.50m. It is to be…

Q: Determine the LRFD factored load for the following situations on a steel column (Ignore any roving…

A: Factored load : A service load multiplied by a load factor yields factored design loads. Service…

Q: 2. Load Tracing For the load-tracing problem below, construct a series of FBDs and show the…

Q: Considering the given cantilever beam, columns and their cross-sections in figure 2, then justify…

A: Beam: Maximum bending moment on the beam is Mmax Mmax=50 kN×3 m=150 kNm=150×106 Nmm Maximum bending…

Q: Q2: Design a typical interior flat slab panel 18x15ft as shown in the figure rested on squared…

A: Solution: Given: slab panel = 18 x 15 ft squared column = 21 x 21 in slab thickness = 14 in DL = 32…

Q: By assuming the slab width is 1.0 meter, please design the both end and middle span concrete slab by…

Q: Structure steel building frequently are designed with diagonal bracing system to resist lateral…

A: Given:- The loads on a certain bracing system of the buildings are:- Dead load = 133 kN Occupancy…

Q: Q2) For the slab shown in Fig.(2),find the allowable live load for the section 1-1. Use f'c-25 MPa,…

A: Solution: Given: fc = 25 MPa fy = 350 MPa Beam dimension = 250 mm x 600 mm h = L/24 h =…

Q: d) Calculate the first story column axial load capacity using 8-#11. Verify that the column size and…

A: Answer (d) Calculation of axial load capacity of square column We know that Axial load capacity is…

Q: Calculate the dead and live loads (separately) applied on column D at the first floor Note:…

A: Calculate the dead and live loads (separately) applied on column D at the first floor Note:…

Q: Sketch #1 shows a three stage working deck personnel scaffold suspended from TWO OUTRIGGER BEAMS…

A: These days, in current tall structures, horizontal deflection prompted by wind or tremor powers are…

Q: 4.7 The cross section of a conventionally reinforced concrete one-way slab is shown below. Using ACI…

A: Consider the given one-way slab.

Q: D 30-0¹ Member Solid one- way slabs B4 Beams or ribbed one- way slabs B4 B4 B3 Column- 52 30-0 Bean-…

A: Minimum girder thickness

Q: Problem 2 Figures on page 3 show the partial framing plan and elevations of a three story steel…

Concept explainers

Applications of Concrete Framing Systems

A concrete frame is a structure formed by the interconnection of beams and columns to form a structural network. In simple terms, it is the basic skeletal structure of a building or any construction. The concrete framing structure is built on a concrete foundation that forms the base of the entire structure. The concrete frame system is built to support floors, roofs, walls, beams, rafters, joists, etc.

Question

100%

The concrete girders shown in the photo of the passenger car park-
ing garage span 30 ft and are 15 ft on center. If the floor slab is 5 in.
thick and made of reinforced stone concrete, and the specified live
load is 50 lb/ft? (see Table 1–4), determine the distributed load the
floor system transmits to each interior girder.
TABLE 1-4 Minimum Live Loads*
Live Load
Live Load
Occupancy or Use
psf
kN/m?
Occupancy or Use
psf
kN/m?
Assembly areas and theaters
Fixed seats
Movable seats
Residential
60
2.87
Dwellings (one- and two-family)
Hotels and multifamily houses
40
1.92
100
4.79
Garages (passenger cars only) 50
Office buildings
Lobbies
2.40
Private rooms and corridors
40
1.92
Public rooms and corridors
Schools
Classrooms
Corridors above first floor
100
4.79
100
4.79
Offices
50
2.40
40
1.92
Storage warehouse
Light
Нeavy
80
3.83
125
6.00
11.97
250
*Reproduced with permission from Minimum Design Loads for Buildings and Other Structures, ASCE/SEI 7-10.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Applications of Concrete Framing Systems

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

HW 3 Determine the column loads assuming: DL (decking, flooring, etc.) = 10 psf LL (occupancy) = 40 psf 50 psf Total Beam B-2 spans between girder G-3 and column B-2 and beam B-3 spans between girder G-3 and column C-2. K 10¹ G3 B GI OPEN B-2 DECKING Sad 8th of Makacals for Architecture and Buidhey Construction, 4adion Dry Ca 23 a G2 D DECKING) B-3 TYPICAL FLOOR FRAMING 2012, 2007 2002, 1999 by Pearson Higher Education, Inc Upper Bade River New Jersey 0745 Al Fogrs Reserved
Three Strength Class C16 sawn timber joists are bolted together to create a trimmer beam which supports the first floor of a new house. The top flange of the trimmer joist is laterally restrained. The floor load is the usual dead and imposed in a domestic property. What is the design moment resistance of one of this group of joists? Joist width-60 mm Joist height-212 mm Give your answer to one decimal place in kNm.
Determine the number of a glulam column 3.0 m in length that support an axial load of 120 kN. The column is to be built with 35mm thick and 200mm wide laminations of Yakal lumber (E = 9.78 GPa, Fc = 15.8 MPa). Assume a normal load duration, wet service condition and fixed-end connection with lateral support at both ends.
2. Roof joists are spaced at 2m and span 6m between supporting girders, and joist depth of 600mm. The allowable deflection limits for OWSJ are L/360 under snow load. The OWSJS are subjected to a dead load of 2.96kPa which includes the estimate joist weight of 0.15kPa, an occupancy load of 2.4kPa, and the following: SULS 1.99kPa SSLS = 1.25kPa Select a suitable OWSJ which satisfies the limit states design.
Per the ACI, what is the minimum girder depth (Select a uniform depth for all girders) Material properties are: - Concrete weight: wt = 150 pcf - Concrete compressive strength: f' = 4000 psi - Steel tensile strength: fy = 60 ksi - Stirrup consists of #4 bar - Framing members are not exposed to weather or in contact with soil. Answer from: 24", 30", 36", 28" 30-0¹ B4 Member Solid one- way slabs D4 83 Colm - % 30-07 Dean /16 -Sab Mark 3 co B 30/0 82 D2 TABLE 9.5(a) MINIMUM THICKNESS OF NONPRESTRESSED BEAMS OR ONE-WAY SLABS UNLESS DEFLECTIONS ARE CALCULATED U/18.5 -Ginder 15 Minimum thickness, h One end Both ends Simply supported continuous continuous Cantilever Members not supporting or attached to partitions or other construction likely to be damaged by large deflections €20 1/24 /28 /10 40-0 Beams or ribbed one- way slabs Notes: Values given shall be used directly for members with normalweight concrete and Grade 60 reinforcement. For other conditions, the values shall be modified as…
Subject is reinforced concrete design please show all steps and solve all parts thank you
Can you please solve the calculations with equations and step by step and use space Gass software for diagrams?I will be grateful to you for this help.All the best and Thank you so much in advance.