Subject is reinforced concrete design please show all steps and solve all parts thank you P01: For the continuous floor system in Fig 1 below, calculate the following:a. be for the beam T-section at section A-A and B-B,b. Design moment for Doubly Reinforced Rectangular beam section (Fig. 4) at section C-C.c. Design moment for Singly reinforced T- beam section (Fig. 2) at section A-A. (See Hint)d.Design moment for Doubly reinforced T- beam section (Fig. 3) at section B-B. (Optional-forfurther knowledge)Given:a.bw = 1 ft;b. f'c = 4000 psi and fy = 60 ksi.C.Central floor beam spanning in horizontal direction.d. The floor system has a uniform spacing between beams.HINT: For a typical floor system, mid-span sections are subjected to positive bending. Section A-A has alarge compression zone; hence compression steel may not be required for additional moment strength inthis case. Assuming section will include No. 3 or No. 4 stirrups (compression steel in the section is notshown in the figure which is placed for reinforcement continuity requirements), d= 24 in- 3.5 in= 20.5 inand d 24 in - 2.5 in = 21.5 in).Slab thickness= 5 in.24 ftFigure 1 Continuous Floor System110 ft10 ft 3 No. 5 barsbe= 72 in.6 No. 7 bars12 in.Figure 2 T-Beam section at A-A sectionI 3.5 in.b₂ = 72 in.13 No. 8 bars2 No. 8 (No. 25)3 No. 7 bars●12 in.6 No. 10 (No. 32) -I=2.5 in.Ism.15 in.Figure 3 T-Beam Section at B-B section12"2.5 in.3 No. 5 bars24"Figure 4 Rectangular Beam Section at C-C24 in.5 in.24 in.

Answered: Image /qna-images/answer/eedeb69c-269c-4828-9c91-a5575430db6d.jpg

P01: For the continuous floor system in Fig 1 below, calculate the following: a. be for the beam T-section at section A-A and B-B, b. Design moment for Doubly Reinforced Rectangular beam section (Fig. 4) at section C-C. c. Design moment for Singly reinforced T-beam section (Fig. 2) at section A-A. (See Hint) d. Design moment for Doubly reinforced T- beam section (Fig. 3) at section B-B. (Optional-for further knowledge) Given: a. bw = 1 ft; b. f'c = 4000 psi and fy = 60 ksi. c. Central floor beam spanning in horizontal direction. d. The floor system has a uniform spacing between beams.

P01: For the continuous floor system in Fig 1 below, calculate the following: a. be for the beam T-section at section A-A and B-B, b. Design moment for Doubly Reinforced Rectangular beam section (Fig. 4) at section C-C. c. Design moment for Singly reinforced T-beam section (Fig. 2) at section A-A. (See Hint) d. Design moment for Doubly reinforced T- beam section (Fig. 3) at section B-B. (Optional-for further knowledge) Given: a. bw = 1 ft; b. f'c = 4000 psi and fy = 60 ksi. c. Central floor beam spanning in horizontal direction. d. The floor system has a uniform spacing between beams.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Differentiate between the following:…

A: slab - its the flat plate element in the building having some thickness to resist the moment and…

Q: Designers typically specify longitudinal reinforcement on all four sides of a square column cross…

A: Brief concept- Longitudinal reinforcement- The column has longitudinal reinforcement to absorb…

Q: Define the difference in application between open stirrups and closed stirrups in concrete beams?

A: Basically function of the stirrups is to Resist shear stress developed in the beam Hold the main…

Q: Why are the rods are required to have some concrete coverage?

A: The space between the reinforcing rods and the concrete is called as concrete cover. While pouring…

Q: Based on preliminary estimates and the architect’s design, a team member has developed the…

A: The given figure is shown below:

Q: What are the differences between laminated-veneer lumber and glued-laminated members?

A: Glued-Laminated Members Glue laminated wood lumbers also known as gleams are formed of solid swan…

Q: What is adhesive strength testing?

A: Adhesive strength test:

Q: Yト 2" ×小

A: Given data Composite member Dimensions To find Centroid

Q: What are the main two differences between a pre-tensioning system and an unbonded post- tensioning…

A: In pre-tensioning system, the tendons are pre-stressed before the concrete is poured or hardened.…

Q: What is the Gypsum Board ? please explain it in details and usage

A: Uses and Advantages:Gypsum is utilized to plaster to provide a smooth, crack-free surface. Gypsum…

Q: What are the main applications of concrete framing systems in construction?

A: Modern construction relies on concrete framing systems because they provide a solid foundation and…

Question

Subject is reinforced concrete design please show all steps and solve all parts thank you

P01: For the continuous floor system in Fig 1 below, calculate the following:
a. be for the beam T-section at section A-A and B-B,
b. Design moment for Doubly Reinforced Rectangular beam section (Fig. 4) at section C-C.
c. Design moment for Singly reinforced T- beam section (Fig. 2) at section A-A. (See Hint)
d.
Design moment for Doubly reinforced T- beam section (Fig. 3) at section B-B. (Optional-for
further knowledge)
Given:
a.
bw = 1 ft;
b. f'c = 4000 psi and fy = 60 ksi.
C.
Central floor beam spanning in horizontal direction.
d. The floor system has a uniform spacing between beams.
HINT: For a typical floor system, mid-span sections are subjected to positive bending. Section A-A has a
large compression zone; hence compression steel may not be required for additional moment strength in
this case. Assuming section will include No. 3 or No. 4 stirrups (compression steel in the section is not
shown in the figure which is placed for reinforcement continuity requirements), d= 24 in- 3.5 in= 20.5 in
and d 24 in - 2.5 in = 21.5 in).
Slab thickness= 5 in.
24 ft
Figure 1 Continuous Floor System
1
10 ft
10 ft

3 No. 5 bars
be= 72 in.
6 No. 7 bars
12 in.
Figure 2 T-Beam section at A-A section
I 3.5 in.
b₂ = 72 in.
13 No. 8 bars
2 No. 8 (No. 25)
3 No. 7 bars
●
12 in.
6 No. 10 (No. 32) -
I=2.5 in.
Ism.1
5 in.
Figure 3 T-Beam Section at B-B section
12"
2.5 in.
3 No. 5 bars
24"
Figure 4 Rectangular Beam Section at C-C
24 in.
5 in.
24 in.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Given

VIEW

Step 2: Effective flange width for T beam

VIEW

Solution

VIEW

Step 3: Analysis of doubly beam

VIEW

Step 4: Equilibrium equation for doubly beam

VIEW

Step 5: Design moment capacity of doubly beam

VIEW

Step 6: Analysis of singly T-beam

VIEW

Step 7: Design moment capacity of singly T-beam

VIEW

Step 8: Analysis of doubly T-beam

VIEW

Step 9: Analysis of doubly T-beam

VIEW

Step 10: Design moment capacity of doubly T-beam

VIEW

Step by step

Solved in 11 steps with 35 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Before any system of precast concrete flooring is put in consideration, several factors must be put into account; mention some of these factors
Why reinforcement is provided in the concrete structure?
What are the requirements for the connection between the wind-resistance column and the roof truss? How to achieve these requirements through structural measures? Subject: Concrete & Masonry Structure
+ „blackboard.com/ultra/courses/_96287_1/cl/outline Question Completion Status: 4 8 9 10 A two span beam subjected to shear and flexure only is reinforced as follows: SECTION @ MIDSPAN @ FACE OF SUPPORTS TOP BARS 2-020 mm 5-Ø20 mm BOTTOM BARS 3-020 mm 2-020 mm Given: Stirrup diameter, ds = 10 mm Concrete fc = 21 MPa Steel rebar = 415 MPa Stirrup fy = 275 MPa %3D Beam size b xh = 270 mm x 450 mm Assume all bars laid out in single layer. Calculate the following: Tensile steel ratio in positive bending at midspan = (in 5 decimal places) kN m (nearest whole Design Moment strength of section at midspan for positive bending = 32°C Light rain ^ O O G ) ENG 1:42 pm ロ

Question 38 A simply supported beam 300 mm wide, 500 mm deep and spans 5 m supports a service super imposed dead load of 6 kN/m and service live load of 9 kN/m. Concrete strength f’c = 21 MPa and steel yield strength fy = 415 MPa. Concrete cover to bar centroid is 70 mm. Determine the required amount of tensile reinforcement in mm^2 as per provisions of NSCP 2015. Write your final answer to the nearest whole number.
What are the differences between ordinary timber and mass timber?
Explain the how to calculate the pitch of the helical reinforcement.
I need the answer as soon as possible
The person that’s accountable for designing the structural plans is known as a professional _____________________. The _____________________ and columns are critical components in the beginning stage of the project. The _______________ notes provides detail information about the grade of concrete and steel. The__________________ and alphabets [A-D] on a set of plans are used as reference points. Site plans are also knowns as ___________ plans. Label dimensions always win out or have precedent over measured dimensions. true or false The Scales usually used to design floor plan are 1/8” Thur 1’ scale. true or False
Q#3: Design Rcc slab for an Isolated Living room resting on masonry walls with following data: Room size = 12' x 26', Service live load = 40 psf , Roof Insulation = 25 psf , fc'=3 ksi , fy=40 ksi Note: Solve the problem on this sheet comment on steel spacing & diameter that you have selected from selection table A-4 already provided in design problems lecture Note: Write the answer in word format Subject: Reinforced Concrete Design 2
Minimum reinforcement in column?
What factors do you consider when designing a tension member in a steelstructure?