(e) Cl, (g) + OH (aq) (f) H,0,(aq) + MnO," (aq) 40. Balance each of the following equations according to the half-reaction method: → Cl (aq) + CIO, (aq) (in base) → Mn" (aq) + O,(g) (in acid) → NO, (aq)+ NO, (aq) (in base) Fe2" (aq) + I,(aq) (g) NO,(g) - (h) Fe* (aq) + I(aq) > Solution (e) 3Cl, (g) + 60H (aq) (f) 5H2O2 (aq) + 6 H* (aq) + 2MnO4 (aq) → 2Mn2+ (aq) + 502 (g) + 8 H2O (1) (g) 2NO,(g)+ 20H (aq) (h) 2Fe" (aq) + 21¯ (aq) · → 5CI (aq) + ClO, (aq) + 3H,0(1); NO, (aq) + NO, (aq) + H,O(1); 2Fe (aq)+I, (aq) 018
(e) Cl, (g) + OH (aq) (f) H,0,(aq) + MnO," (aq) 40. Balance each of the following equations according to the half-reaction method: → Cl (aq) + CIO, (aq) (in base) → Mn" (aq) + O,(g) (in acid) → NO, (aq)+ NO, (aq) (in base) Fe2" (aq) + I,(aq) (g) NO,(g) - (h) Fe* (aq) + I(aq) > Solution (e) 3Cl, (g) + 60H (aq) (f) 5H2O2 (aq) + 6 H* (aq) + 2MnO4 (aq) → 2Mn2+ (aq) + 502 (g) + 8 H2O (1) (g) 2NO,(g)+ 20H (aq) (h) 2Fe" (aq) + 21¯ (aq) · → 5CI (aq) + ClO, (aq) + 3H,0(1); NO, (aq) + NO, (aq) + H,O(1); 2Fe (aq)+I, (aq) 018
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Can Anyone explain step by step（in details）how to balance these equation in half reaction method？
![### Example of Balancing Redox Reactions Using the Half-Reaction Method
#### Task: Balance each of the following equations according to the half-reaction method:
**(e)**
\[ \text{Cl}_2(g) + \text{OH}^-(aq) \rightarrow \text{Cl}^-(aq) + \text{ClO}_3^-(aq) \, \text{(in base)} \]
**(f)**
\[ \text{H}_2\text{O}_2(aq) + \text{MnO}_4^-(aq) \rightarrow \text{Mn}^{2+}(aq) + \text{O}_2(g) \, \text{(in acid)} \]
**(g)**
\[ \text{NO}_2(g) \rightarrow \text{NO}_3^-(aq) + \text{NO}_2^-(aq) \, \text{(in base)} \]
**(h)**
\[ \text{Fe}^{3+}(aq) + \text{I}^-(aq) \rightarrow \text{Fe}^{2+}(aq) + \text{I}_2(aq) \]
---
#### Solution:
**(e)**
\[ 3\text{Cl}_2(g) + 6\text{OH}^-(aq) \rightarrow 5\text{Cl}^-(aq) + \text{ClO}_3^-(aq) + 3\text{H}_2\text{O}(l) \]
**(f)**
\[ 5\text{H}_2\text{O}_2(aq) + 6\text{H}^+(aq) + 2\text{MnO}_4^-(aq) \rightarrow 2\text{Mn}^{2+}(aq) + 5\text{O}_2(g) + 8\text{H}_2\text{O}(l) \]
**(g)**
\[ 2\text{NO}_2(g) + 2\text{OH}^-(aq) \rightarrow \text{NO}_3^-(aq) + \text{NO}_2^-(aq) + \text{H}_2\text{O}(l) \]
**(h)**
\[ 2\text{Fe](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feb62ec4b-b625-4332-acd2-c86081f32c3c%2F14679f77-827a-4862-ba46-4944c7df6113%2Fmoyiqp6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Example of Balancing Redox Reactions Using the Half-Reaction Method
#### Task: Balance each of the following equations according to the half-reaction method:
**(e)**
\[ \text{Cl}_2(g) + \text{OH}^-(aq) \rightarrow \text{Cl}^-(aq) + \text{ClO}_3^-(aq) \, \text{(in base)} \]
**(f)**
\[ \text{H}_2\text{O}_2(aq) + \text{MnO}_4^-(aq) \rightarrow \text{Mn}^{2+}(aq) + \text{O}_2(g) \, \text{(in acid)} \]
**(g)**
\[ \text{NO}_2(g) \rightarrow \text{NO}_3^-(aq) + \text{NO}_2^-(aq) \, \text{(in base)} \]
**(h)**
\[ \text{Fe}^{3+}(aq) + \text{I}^-(aq) \rightarrow \text{Fe}^{2+}(aq) + \text{I}_2(aq) \]
---
#### Solution:
**(e)**
\[ 3\text{Cl}_2(g) + 6\text{OH}^-(aq) \rightarrow 5\text{Cl}^-(aq) + \text{ClO}_3^-(aq) + 3\text{H}_2\text{O}(l) \]
**(f)**
\[ 5\text{H}_2\text{O}_2(aq) + 6\text{H}^+(aq) + 2\text{MnO}_4^-(aq) \rightarrow 2\text{Mn}^{2+}(aq) + 5\text{O}_2(g) + 8\text{H}_2\text{O}(l) \]
**(g)**
\[ 2\text{NO}_2(g) + 2\text{OH}^-(aq) \rightarrow \text{NO}_3^-(aq) + \text{NO}_2^-(aq) + \text{H}_2\text{O}(l) \]
**(h)**
\[ 2\text{Fe
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