e) 17 J/K Question 11 (0.5 points) 700K =-13.457 kJ. What is K, for this reaction at For the reaction CO(g)+2H,(g) 700. K? O a) 1.00 Ob) 1.54 O c) 10.1 O d) 2.31 Oe) none of these Question 12 (0.5 points) According to the first law of thermodynami AE is olu

e) 17 J/K Question 11 (0.5 points) 700K =-13.457 kJ. What is K, for this reaction at For the reaction CO(g)+2H,(g) 700. K? O a) 1.00 Ob) 1.54 O c) 10.1 O d) 2.31 Oe) none of these Question 12 (0.5 points) According to the first law of thermodynami AE is olu

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Please calculate the FREEZING point of A in Celsius using the data below, please show all work thank you!!:)
Using standard heats of formation, determine AH for the following reactions. Report your answers to the nearest 0.1 kJ. X Incorrect. Fe203(s) + 3H20(1) 2Fe(OH)3(s) i -2.90E1 kJ eTextbook and Media Hint Correct. B203(g) + 3H20(1) - 2H3BO3(s) -5.70E1 kJ Save for Later Attempts: 2 of 3 used Submit Answer
Macmillan Learning For a particular reaction at 181.2 °C, AG= -861.43 kJ, and AS 116.09 J/K. Calculate AG for this reaction at -97.7 °C. AG= kJ
Given the information A+ B 2D AH = -759.3 kJ AS = 368.0 J/K C→ D AH° = 432.0 kJ AS = -126.O J/K calculate AG at 298 K for the reaction A +B 2C AG = 1808.06 Incorrect Activate Windo Go to Settings to actro help terms of use contact us careers privacy policy about us
For the reaction N₂ (g) + 3H₂(g) → 2NH3 (9) AG° = -40.9 kJ and AS = 258 K and 1 atm. This reaction is conditions at 258 K. - 198.7 J/K at favored under standard The standard enthalpy change for the reaction of 1.51 moles of N₂ (g) at this temperature would be kJ.
DATA AND CALCULATIONS Reaction 2 Reaction 3 Reaction 1 (no solid NaoH) 2154 100. 154 a8.5 Mass of NaOH solid 100 t00.061 34.8 d1.9 Mass (total) of solution 6. 9. 6. °C 33.3 °C Final temperature, T2 °C av. °C al. 7 Initial temperature, T °C °C CALCULATIONS temperature change, AT 6.7 °C la. 9 °C I1.6 °C kJ -5395.489 k-4848.8 -ag04.913 a804.913 k- $395.499 KJ|-4848.8 Heat, q kJ ΔΗ k) Moles of NaOH 0.054 mol 0.0515 0.05 mol mol AH/mol -51,942.83k)/mol-104 96.70kJ/mol-96 976 kJ/mol Experimental value kJ/mol Accepted value k)/mol Percent error %
2.4
The equation for ATP hydrolysis is H₂O ATP→ ADP + P₁ AG"=-30.5 kJ/mol Calculate AG for ATP hydrolysis to arrange the conditions from most favorable to least favorable. A 37.0 °C and R = 8.315 J/(mol K). . ATP hydrolysis most favorable ATP hydrolysis least favorable Answer Bank muscle: [ATP] = 8.1 mM; [ADP] = 0.9 mM; [Pi] = 8.1 mM brain: [ATP] = 2.6 mM; [ADP] = 0.7 mM; [Pi] = 2.7 mM liver: [ATP] = 3.4 mM; [ADP] = 1.3 mM; [Pi] = 4.8 mM
2req For the reaction 2req 2NO(g) + 2H2(g) N2(g) + 2H20() 2req AH° = -752 kJ and AS° = -352 J/K 2req AG° would be less than zero at temperatures (above, below) K. 2req Enter above or below in the first box and enter the temperature in the second box. Assume that AH° and AS° are constant.
Consider the reaction 4HCI(g) + O₂(g)- +2H₂O(g) + Using the standard thermodynamic data in the tables linked above, calculate AG for this reaction at 298.15K if the pressure of each gas is 13.76 mm Hg. ANSWER: 187.91 2Cl₂(g) kJ/mol
3. Calculate AS at 25°C and 1 atm pressure in J/(mol-K) for the following reaction CH4(8) + N₂(g) + 164 kJ → HCN(g) + NH3(8) AG° = 159 kJ. [a] 1x10² [b] 2 [c] 4x10² [d] 2x10¹ [e] 7x10¹
Examine the AH values given for a series of gaseous reactions that are listed below. Reaction 1: -84.9 kJ Reaction 2: 235 kJ Reaction 3: -66.7 kJ Reaction 4: 0.779 kJ For which reactions will the K, decrease with increasing temperature? Select all that apply. 04 1 3 The equilibrium constant does not change with temperature. 02